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2 years ago

Which equation can be used to find the area of the blue triangle?

Mathematics

2 answers:

kvv77 [185]2 years ago

5 0

Answer: B) A=1/2(7)(12).

Explanation: The formula for area of a triangle is 1/2bh. Only B maintains this formula.

Naddik [55]2 years ago

3 0

Answer:

The answer is D. A=1/2(7 to the power of 2) 12 to the power of 2)

Step-by-step explanation:

You might be interested in

Solving Proportions 19/4 = x/4

fredd [130]

Answer:

x = 19

Step-by-step explanation:

To solve proportions, you first need to cross multiply. $\frac{19}{4}= \frac{x}{4}$ , you would need to multiply each top number by 4. 76 = 4x, which then could easily be simplified down to 19 by just dividing by four.

7 0

3 years ago

HELP PLEASE.........

sleet_krkn [62]

Answer: $\bold{\dfrac{41}{80}}$

<u>Step-by-step explanation:</u>

$\dfrac{puppies}{total}+\dfrac{kittens}{total}+\dfrac{unicorns}{total}\\\\\\=\dfrac{15}{80}+\dfrac{16}{80}+\dfrac{10}{80}\\\\\\=\large\boxed{\dfrac{41}{80}}$

5 0

3 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

A number, X, rounded to 1 decimal place is 3,7<br> Write down the error interval for x,

sp2606 [1]

Answer:

The error interval for x is:

[3.65,3.74]

Step-by-step explanation:

The number after rounding off is obtained as:

3.7

We know that any of the number below on rounding off the number to the first decimal place will result in 3.7:

3.65 3.66 3.67 3.68 3.69 3.70 3.71 3.72 3.73 3.74

( Because if we have to round off a number present in decimals to n place then if there is a number greater than or equal to 5 at n+1 place then it will result to the one higher digit at nth place on rounding off and won't change the digit if it less than 5 )

Hence, the error interval is:

[3.65,3.74]

6 0

3 years ago

How many triangles can be constructed with angles measuring 60 degrees 60 degrees and 40 degrees

erma4kov [3.2K]

None, a triangle need to have angles measuring 180 degrees , its only possible if the triangle has three angles equaling 60

8 0

3 years ago

Read 2 more answers