For #3, you just have to plug in the numbers for x.
It tells you what to substitute for x in the question. (x = 0, 1, 2, 3, 4, 5, and 6)
For example, let's substitute 0 for x.
6x - x² (the 2 means square the number, or multiply it by itself)
6(0) - (0)²
0 - 0
= 0.
You'll do that to all the numbers (1-6) and fill out the table.
For #4, you have to solve using the distributive property to find out if the equations on both sides are equal.
I'll do the first one for you.
6a - 8 = 2 (3a - 5)
6a - 8 = 6a - 10
They're not equal.
Answer:
Step-by-step explanation:
Given that every day at noon, a bus leaves for Townville and travels at a speed of x kilometers per hour. Today, the bus left 30 minutes late.
If the driver drives 7/6 times as fast as usual, she will arrive in Townville at the regular time.
If correct time leaves then distance = time *speed
280 = t*x where t is the time in hours
Or t = 280/x
Now speed changes to 7x/6 while time changes to (t-1/2)
So 280 = (t-1/2) 7x/6
x = 80 km per hour
Answer:
Solution 1: 1+1
Solution 2: 1-
Step-by-step explanation:
x^2-2=2x
x^2-2x-2=0
Use quadratic equation.
(-b+-)/2a
(2+-)/2
(2+-)/2
(2+-)/2
Solution 1: (2+2)/2=1+1
Solution 2: 1-
60×1.5=90 1.5 hours equals 10:30
9:30 + one hour equals 10:30 and 90 miles away
In conclusion they will meet at 10:30