What am I doing wrong?

Mathematics

1 answer:

NemiM [27]2 years ago

8 0

Im afraid I cant make out the document bu this is how to solve it:-

First find the slope of the line

slope = rise / run = (7-2) / (5- - 1) = 5/6

Now use the point-slope form of equation of a straight line:-

y - y1 = m (x - x1) where m= slope and (x1, y1) is a point on the line. Use the point (-1, 2):-

y - 2 = (5/6) (x + 1)

multiply through by 6:-

6y - 12 = 5(x + 1)

6y - 12 = 5x + 5

-12 = 5x - 6y + 5

-17 = 5x - 6y

Flipping it over:-

5x - 6y = -17

5x - 6y = -37

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Sid starts with savings of £13

MAVERICK [17]

Answer:

The savings of Sid and Tim will be in 17:9 in 6 weeks.

Step-by-step explanation:

Initial savings of Sid = £ 13

Initial savings of Tim = £ 0

For each successive week Sid saved = £ 3.5

For each successive week Tim saved = £ 3

Let us assume that after "x weeks" the amounts of Sid and Tim are in ratio 17:9.

If Sid saves £ 3.5 in one week, in x weeks he will £ 3.5x. Since he had £ 13 initially, total amount he would have in x weeks will be £ (13 + 3.5x)

If Time saves £ 3 one week, in x weeks he will save £ 3x. Since, he didn't have any money initially, in x weeks he would have saved £ 3x

The ratio of their savings in x weeks would be 17:9

So,

Sid's saving : Tim's saving = 17 : 9

Using the values of expressions, we get:

$13+3.5x:3x=17:9\\\\\frac{13+3.5x}{3x}=\frac{17}{9}\\\\ 9(13+3.5x)=17(3x)\\\\ 117+31.5x=51x\\\\ 117=51x-31.5x\\\\ 117=19.5x\\\\ x=\frac{117}{19.5}\\\\ x=6$