Question

The magnetic field inside a 5.0-cm-diameter solenoid is 2.0 T and decreasing at 3.60 T/s.Part AWhat is the electric field strength inside the solenoid at a point on the axis?Express your answer as an integer and include the appropriate units.E = Part BWhat is the electric field strength inside the solenoid at a point 1.50cm from the axis?Express your answer to three significant figures and include the appropriate units.E =

Answer 1

To solve this problem it is necessary to apply the concepts related to the electric field within a solenoid. Physically called the electric field is the area of space at whose points the definition of the intensity of an electric force is specified.

Inside the solenoid the electric field inside it can be defined as

$E_{i} = \frac{r}{2} (\frac{dB}{dt})$

The electric field at a point on the axis of the solenoid is

$E = \frac{0}{2} (\frac{dB}{dt}) \rightarrow r = 0$

$E = 0$

Therefore the electric field strength inside the solenoid at a point on the axis is Zero.

Part B) The electric field at a point on the axis of the solenoid is

$E = \frac{1.5*10^{-2}}{2} (3.6)$

$E = 0.027V/m$

$E = 2.7*10^{-2} V/m$

Therefore the electric field strength inside the solenoid at a point 1.5cm from the axis is $2.7*10^{-2} V/m$