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erastova [34]
4 years ago
13

A 2.1 m long straight horizontal wire carrying a current of 5.1 A along the +x-direction is in a region of uniform magnetic fiel

d, B. If the mass of this wire is 0.2 kg, find the magnitude and direction of the magnetic field necessary to have this wire "float" in the Earth's gravitational field. (Assume the force due to gravity is in the −y-direction.)
Physics
1 answer:
Veseljchak [2.6K]4 years ago
8 0

Explanation:

It is given that,

Length of the wire, L = 2.1 m

Current, I = 5.1 A

Mass of the wire, m = 0.2 kg

Let B is the magnitude of the magnetic field necessary to have this wire "float" in the Earth's gravitational field such that,

F_g=F_m

mg=ILB

B=\dfrac{mg}{IL}

B=\dfrac{0.2\times 9.8}{5.1\times 2.1}

B = 0.18 T

The direction of magnetic field is given by Fleming's left hand rule. Here, the magnetic field is in +x direction.

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