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anastassius [24]
3 years ago
14

Un vehicle surt, en un instant, d'un punt A cap a un altre punt B amb una velocitat constant de 36 km/h. Després d'un minut(60 s

egons) un altre vehicle surt de B cap a A, partint del repòs, amb una acceleració d'1 m/s2. Sabent que la distància entre A i B és de 3 km, a quina distància de A es trobaran els vehicles? (SOL:1200m)
Physics
1 answer:
kati45 [8]3 years ago
6 0



Ask Siri or goggle has all answers



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The Sun appears at an angle of 48.4° above the horizontal as viewed by a dolphin swimming underwater. What angle does the sunlig
Luden [163]

Answer:

4.57 degree

Explanation:

As the dolphin is under water, so the angle is angle of refraction which is equal to 48.4 degree.

refractive index of water, n = 1.333

Let the angle of incidence which is the angle between the incident ray and the normal is i.

By use of Snell's law

n = \frac{Sin i}{Sin r}

1.333 = \frac{Sin i}{Sin 48.4}

Sin i = 1.333\times Sin 48.4 = 0.9968

i = 85.43 degree

Angle made with the horizon = 90 - 85.43 = 4.57 degree

6 0
3 years ago
Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?​
telo118 [61]
  • Force=12N
  • Work=9J

\\ \sf\longmapsto W=Fd

\\ \sf\longmapsto d=\dfrac{W}{F}

\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m

6 0
2 years ago
Read 2 more answers
Consider a rectangular ice floe 5.00 m high, 4.00 m long, and 3.00 m wide. a) What percentage of the ice floe is below the water
artcher [175]

Answer:

(a) 92 %

(b) 6.76 %

Explanation:

length, l = 4 m, height, h = 5 m, width, w = 3 m, density of water = 1000 kg/m^3

density of ice = 920 kg/m^3, density of mercury = 13600 kg/m^3

(a) Let v be the volume of ice below water surface.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of water x g = Total volume of ice block x density

                                                                      of ice x g

v x 1000 x g = V x 920 x g

v / V = 0.92

% of volume immersed in water = v/V x 100 = 0.92 x 100 = 92 %

(b) Let v be the volume of ice below the mercury.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of mercury x g = Total volume of ice block x  

                                                                      density of ice x g

v x 13600 x g = V x 920 x g

v / V = 0.0676

% of volume immersed in water = v/V x 100 = 0.0676 x 100 = 6.76 %

4 0
3 years ago
Which of the following is not true of a conductor? A. It is used in electrical circuits. B. It allows easy passage of moving cha
Oksi-84 [34.3K]
Three of the statements are true.  'D' is false.
Glass and rubber are excellent insulators, total duds as conductors.
8 0
2 years ago
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15 Points , Physics HW, can someone please show me step by step how to calculate percent difference for this problem. My numbers
timofeeve [1]

The percent difference between two numbers x and y is given by

\dfrac{|y-x|}x \times 100\%

The absolute value is there because we only care about the absolute percent difference, and not taking into account whether we go from x to y or vice versa. If we remove them, we have two possible interpretations of percent difference.

For example, the (absolute) percent difference between 3 and 6 is

\dfrac{|6-3|}3 \times 100\% = 100\%

In other words, we add 100% of 3 to 3 to end up with 6. This is the same as the percent difference going from 3 to 6. On the other hand, the percent difference going from 6 to 3 is

\dfrac{3-6}3\times100\%=-50\%

which is to say, we take away 50% of 6 away from 6 to end up with 3.

"Make comparisons to object measurements" tells us that the differences should be computed relative to "measurements for object". In other words, take x from the left column and y from the right column.

\dfrac{|7.1-7.3|}{7.1} \times 100\% \approx 2.82\%

\dfrac{|4.8-5.0|}{4.8} \times 100\% \approx 4.17\%

\dfrac{|7.2-7.5|}{7.2} \times 100\% \approx 4.17\%

3 0
2 years ago
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