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gregori [183]
4 years ago
15

Which part of a circuit changes electrical energy into another form of energy

Physics
1 answer:
aniked [119]4 years ago
6 0

Answer:

The reactive part of a circuit changes electrical energy into another form of energy.

Explanation:

The reactive part of a circuit changes electrical energy into another form of energy.

The inductive part of a circuit changes electrical energy to magnetic energy and the capacitive part of a circuit changes electrical energy to electrostatic energy.

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Objects falling through the air experience a type of friction called air resistance
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True is the answer ndndndjjdjd
8 0
3 years ago
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The answer is A and no matter how many times I tried I can't get it.
ryzh [129]
Imagine a skinny straw in the water, standing right over the hole. The WEIGHT of the water in that straw is the force on the tape. Now, the volume of water in the straw is (1 mm^2) times (20 cm). Once you have the volume, you can use the density and gravity to find the weight. And THAT's the force on the tape. If the tape can't hold that force, then it peels off and the water runs out through the hole. /// This is a pretty hard problem, because it involved mm^2, cm, and m^3. You have to be very very very careful with your units as you work through this one. If you've been struggling with it, I'm almost sure the problem is the units.
5 0
3 years ago
The resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is:a) 180 d
r-ruslan [8.4K]

Answer:

0 degrees

Explanation:

Let F_1\ and\ F_2 are two forces. The resultant of two forces acting on the same point is given by :

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos\theta}

Where \theta is the angle between two forces

When \theta=0 i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos(0)}

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2}

When \theta=90^{\circ} i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+F_1F_2\ cos(90)}

F_R=\sqrt{F_1^2+F_2^2}

When \theta=180^{\circ} i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+F_1F_2\ cos(180)}

F_R=\sqrt{F_1^2+F_2^2-2F_1F_2}

It is clear that the resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is 0 degrees. Hence, this is the required solution.

8 0
3 years ago
Which statement best describes the difference between a substance with a pH of 3.0 and a substance with a pH of 6.0?
satela [25.4K]

The statement best describes the difference between a substance with a pH of 3.0 and a substance with a pH of 6.0 is - The substance with the lower pH has 1,000 times as many hydrogen ions per volume of water.

pH is the scale or measure for the substance about its acidic or basic strength. It ranges from 0 to 6.9 which is acidic and 7.1 to 14 which is basic.

Acidic substance has high concentration of Hydrogen ions whereas, basic substance has low concentration of hydrogen ions, however for the OH⁻ ions it is reverse.

  • Concentration of hydrogen ions is inversely related to its pH
  • More hydrogen ions present, the lower the pH
  • The fewer hydrogen ions, the higher the pH We know,

pH = -log(H^{+}) then,  

=> 3 = -log (H^{+})

=> H^{+} =  (for pH = 3)  

=> pH = -log(H^{+})

=> 6 = -log (H^{+})

=> H^{+} = 10^{-6} (for pH = 6)

 Thus, The substance with the lower pH (3) has 1000 times as many hydrogen ions per volume of water.

Learn more about pH scale:

brainly.com/question/1596421

7 0
3 years ago
Two objects with masses m and 3m are connected by a compressed spring so that the energy stored in the spring is 375 joules. If
cluponka [151]

Answer:

281.25 J

Explanation:

We are told that the two objects with masses m and 3m.

Also that energy stored in the spring is 375 joules.

Now, initially the centre of mass of the system took place at rest, it means v1 = v and v2 = v/3

Thus, from principle of conservation of energy, we have;

½mv² + ½(3m)(v/3)² = 375J

(m + 3m/9)½v² = 375

(4/3)m × ½v² = 375

Multiply both sides by ¾ to get;

½mv² = 375 × ¾

½mv² = 281.25 J

Therefore, energy of lighter body is 281.25 J

7 0
3 years ago
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