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yarga [219]
3 years ago
7

Frank was training for a marathon. He ran 1,952 on day 1, 4,567 feet on day 2, and 7,568 feet on day 3. How many feet did Frank

run during his training?
Mathematics
2 answers:
erastovalidia [21]3 years ago
7 0

So far, on his first 3 days of training, Frank has run

         (1,952-ft + 4,567-ft + 7,568-ft)  =  14,087 feet .

So far, in 3 days of training, Frank has run about 10% of the length
of one marathon.  He has a long wayda go.
AfilCa [17]3 years ago
4 0
In the total of three days Frank ran 14,087 feet.
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Vedmedyk [2.9K]
You are investing $2,000 fro 3 months and the APR is 4% so you will get one quarter of the APR for a year. For the year 4% interest is $2,00 x .04 or $80 for the year. # months is 1/4 of a year so divide $80 by 4 to get the interest fro 3 months which is 20 so the answer is B.
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Case Study 2: Maxing out Matched Savings
zhuklara [117]

Answer:

The computation of the given question is shown below:-

Total Contributions = Monthly contribution + Amount invested in Ferdinand’s 401(k)

= $250 + $125

= $375  

1. Future Value = PMT [((1 + r)n - 1) ÷ r

Future value = 375 × ((1 + 0.03 ÷ 12) × 12 × 40 - 1) ÷ (0.03 ÷ 12)

= $347,272

2. Ferdinand deposit = Given Amount × Total number of months in a year × Number of years

= $250 × 12 Months × 40 Years

= $120,000

3. The Amount put in by the employer = 50% of $250 ×Total number of months in a year × Number of years

= $125 × 12 Months × 40 Years

= $60,000

4. Interest = Future value - Ferdinand deposit - The Amount put in by the employer

= $347,272 - $120,000 - $60,000

= $167,272

Step-by-step explanation:

4 0
1 year ago
Fraction strip for 1/4, 2/8,3/12
Brilliant_brown [7]

4/16, 5/20, 6/24, 7/28, 8/32...

7 0
2 years ago
Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 79.
xxMikexx [17]

<u>Answer:</u>

Price of the​ adult's ticket = $13

Price of a​ child's ticket = $ 10

<u>Step-by-step explanation:</u>

Given:

Cost of train fares for Three adults and four children = $79

Cost of train fares Two adults and three children  = $ 56

To Find:

Price of the​ adult's ticket and the price of a​ child's ticket =?

Solution:

Let the cost of one adult's ticket be x  and

Let the cost of one child's ticket be y

Then

Three adults and four children must pay $ 79 be

3x + 4y = 79-----------------------------------------------(1)

Two adults and three children must pay $56

2x + 3y = 56----------------------------------------------(2)

multiply  eq(1) by 2, we get

6x + 8y = 158----------------------(3)

multiply  eq(2) by 3, we get

6x + 9y = 168----------------------(4)

Subracting (3) from (4)

 6x + 9y = 168

 6x + 8y = 158

(-)      (-)       (-)

------------------------------

0x +  y = 10

------------------------------

y=10

Now substitute the value of y in eq (1) to get the value of x

3x + 4(10)= 79

3x +  40 = 79

3x = 79 - 40

3x = 39

x = \frac{39}{3}

x= 13

3 0
3 years ago
How do you determine whether a sum will be positive, negative, or 0 when adding a positive and a negative integer?
professor190 [17]
If the integers have the same absolute value ... they're the same number
but with different signs ... then their sum is zero.

Example:    (plus) 927 added to (negative) 927  =  zero


If the integers have different absolute values ... they're different numbers with different
signs ... then their sum has the same sign as the one with the bigger absolute value.

Examples:

==>   (plus) 92 added to (negative) 91
         92 and 91 are 1 number apart on the number line.
         The positive number is bigger than the negative number.
         So the sum is  +1 . 

==>    (plus) 35 added to (negative) 37
          35 and 37 are 2 numbers apart on the number line.
          The negative number is bigger than the positive one.
          So the sum is  -2 .
3 0
2 years ago
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