Please include the instructions; I assume your job is to find the value of x.
<span>1/(x+1) - 1/(x+2) = 1/2 would better be written as
1 1 1
</span><span>-------- - ------------ = ----
x+1 x+2 2
Identify the LCD. It is (x+1)(x+2)(2). Mult. all 3 terms of the equation by this LCD:
2(x+2) - 2(x+1) = 2(x+1)(x+2)
We can factor out the 2 from all terms:
x+2 - x - 1 = x^2 + 3x + 2
Let's move all terms from the left to the right side:
0 = x^2 + 3x + 2 - x - 2 + x + 1
Then x^2 + 3x + 1 = 0. This is a quadratic with a=1, b=3 and c=1.
What is x?
-3 plus or minus sqrt( 9-4(1)(1) ) -3 plus or minus sqrt(5)
x = --------------------------------------------- = ---------------------------------
2 2
I rather expected to obtain an integer value for x.
Why don't you give this problem a try yourself? Suggestion: First mult. every term by 2. This will give you:
2 2
------- - ------- = 1 and this may be slightly easier to work with. Please
x+1 x+2 give it a try: try to find x that satisfies this equation.
Important: note that x cannot equal either -1 or -2.
</span>
Answer:
a) 54 mph to 144 mph
Step-by-step explanation:
We don't know the shape of the distribution, so we use Chebyshev's Theorem to solve this question. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
At least eight-ninths of the player's serves.
8/9 is approximately 89%
So
Mean: 99, standard deviation: 15
99 - 3*15 = 54
99 + 3*15 = 144
So the correct answer is:
a) 54 mph to 144 mph
Answer:
1/2 or .5
Step-by-step explanation:
you find 2 points that the line goes through, then you find the rise/run. lastly you simplify if you can, then you have the answer
Answer:
156
Step-by-step explanation:
Write 26% as
26
100
Since, finding the fraction of a number is same as multiplying the fraction with the number, we have
26
100
of 600 =
26
100
× 600
Therefore, the answer is 156
If you are using a calculator, simply enter 26÷100×600 which will give you 156 as the answer.
