Given:
1 set requires 4 couples 8 dancers.
Total number of people at a square dance = 250.
To find:
The greatest number of sets possible at the dance.
Solution:
We have,
Total people = 250
1 set = 8 people.



Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

Therefore, the number of possible sets at the dance is 31.
Answer:
Simplifying
T = C(9 + AB) * forB
Reorder the terms for easier multiplication:
T = C * forB(9 + AB)
Multiply C * forB
T = forBC(9 + AB)
T = (9 * forBC + AB * forBC)
Reorder the terms:
T = (forAB2C + 9forBC)
T = (forAB2C + 9forBC)
Solving
T = forAB2C + 9forBC
Solving for variable 'T'.
Move all terms containing T to the left, all other terms to the right.
Simplifying
T = forAB2C + 9forBC
Step-by-step explanation:
Simplifying
T = C(9 + AB) * forB
Reorder the terms for easier multiplication:
T = C * forB(9 + AB)
Multiply C * forB
T = forBC(9 + AB)
T = (9 * forBC + AB * forBC)
Reorder the terms:
Answer:
y=5200(0.85)^x
Step-by-step explanation:
A photocopier is purchased for $5200 and depreciates in value by 15% per year. Which equation best describes the value of the photocopier in years? O.A. y=5200(1.15) OB. y = 5200(0_15) - O cy= 5200(1.85) ODy=5200(0.85)"
Answer:
21060
Step-by-step explanation:
19500÷100=195
195×8=1560
1560+19500=21060