What is the answer to this question?

What is the volume of liquid in this graduated cylinder? Be sure your answer has a reasonable number of decimal places.

Amiraneli [1.4K]

Answer:

76 ml

Explanation:

The complete question is attached in the image.

The volume of a liquid is the amount of space that the liquid occupies or contains. Since for a liquid, it takes the shape of the container, when measuring the volume, we just measure the space occupied by the liquid in the container.

From the image, when determining the volume, we are to use the value of the lower meniscus. Hence the volume of the liquid is gotten to be 76 ml

8 0

3 years ago

PLS HELP ITS URGENT

mamaluj [8]

Answer:

Answer

The answer is option 4

6 0

3 years ago

Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a s

disa [49]

At equilibrium the concentrations of:

[HSO₄⁻] = 0.10 M;

[SO₄²⁻] = 0.037 M;

[H⁺] = 0.037 M;

There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.

HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid. HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.

R $HSO_4^-$ ⇄ $H^+ + SO_4^2^-$

I $0.14$

C $- x$ $+x$ $+x$

E $0.14-x$ $x$ $x$

$K_a = 1.3$ × $10^-^2$ for $HSO^-_4$ . As a result,

$\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a$

$K_a$ is large. It is no longer valid to approximate that $[HSO^-_4]$ at equilibrium is the same as its initial value.

$\frac{x^2}{0.14-y} = 1.3 * 10^-^2$

$x^2+1.3*10^-^2x - 0.14$ × $1.3$ × $10^-^2= 0$

Solving the quadratic equation for $x , x \geq 0$ since $x$ represents a concentration;

$x=0.0366538$

Then, round the results to 2 significant figure;

$[SO_4^2^-] = x = 0.037 mol. L ^-^1$
$[H^+] = x = 0.037 mol. L ^-^1$
$[HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1$

Learn more about concentration here:

brainly.com/question/14469428

#SPJ4

3 0

1 year ago

Sodium hydrogen carbonate , also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid ind

Yanka [14]

Answer:

The mass of NaHCO3 that she would need to ingest to neutralize this much HCl is 1.512g

Explanation:

The question can be better presented as follows:

Sodium hydrogen carbonate NaHCO3, also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid HCl, which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO3 neutralizes excess HCl through this reaction: HCl(aq)+NaHCO3(aq)→NaCl(aq)+H2O(l)+CO2(g)

The CO2 gas produced is what makes you burp after drinking the solution. Suppose the fluid in the stomach of a woman suffering from indigestion can be considered to be 200.mL of a 0.089M HCl solution. What mass of NaHCO3 would she need to ingest to neutralize this much HCl? Be sure your answer has the correct number of significant digits.

SOLUTION

Given:

Volume of HCl = 200ml = 0.200L

Molarity of the HCl =>0.089M

The number of mole of HCl can be calculated using C=n/V

Therefore n = CxV = 0.089 × 0.2

=0.018 moles

Equation for the reaction:

HCl(aq)+NaHCO3(aq)→NaCl(aq)+H2O(l)+CO2(g)

From the equation, 1mole of HCl required 1mole of NaHCO3 for neutralization; therefore 0.018 moles of HCl will require 0.018 moles of NaHCO3.

But molar mass of NaHCO3 = 23+1+12+(16×3) = 84

Finally using number of moles = mass/molar mass

Therefore mass = 0.018 × 84

= 1.512g

8 0

3 years ago

Part 1: Cats falling out of windows

timurjin [86]

Answer:

A cat that falls out of the window even if it seems to be doing well, must urgently go to a veterinary clinic in order to be placed under surveillance for at least 24 to 72 hours

Explanation:

3 0

3 years ago