Answer:
1.552 moles
Explanation:
First, we'll begin by writing a balanced equation for the reaction showing how C8H18 is burn in air to produce CO2.
This is illustrated below:
2C8H18 + 25O2 -> 16CO2 + 18H2O
Next, let us calculate the number of mole of C8H18 present in 22.1g of C8H18. This is illustrated below:
Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol
Mass of C8H18 = 22.1g
Mole of C8H18 =..?
Number of mole = Mass /Molar Mass
Mole of C8H18 = 22.1/144
Mole of C8H18 = 0.194 mole
From the balanced equation above,
2 moles of C8H18 produced 16 moles of CO2.
Therefore, 0.194 mole of C8H18 will produce = (0.194x16)/2 = 1.552 moles of CO2.
Therefore, 1.552 moles of CO2 are emitted into the atmosphere when 22.1 g C8H18 is burned
Answer:
rate = kxyz
Explanation:
It is worth knowing that the rate low can only be determined by experimentation only not by just balancing equations. So here we are told that all the reactants x , y and z are all first order. This is important because we use this as exponents. That is why the exponents of all the reactants will be 1.
rate = kxyz
Answer:
Elasticity or Flexibility
Explanation:
The ability of an object to resume its normal shape after being stretched or compressed is called elasticity
Answer:
b) F
Explanation:
Only non-metals can gain electrons during ionic bonding.
b) F
Li, Mg and K are metals.
Answer:
Cm = Cn/n = 0.1/2 = 0.05 (M)
n = 0.05*2= 0.1 mol
m H2SO4= 0.1*98= 9.8 g
m dd H2SO4= 9.8/ 0.98 =10 g
V= 10/ 1.84 = 5.435 ml
Explanation:
