What is the constant of proportionality of y= 7.25x

Last week a certain brand of hand lotion cost $3.00 for a 16-ounce bottle. this week the hand lotion is on sale for $2.40 for a

Yanka [14]

$3.00-$2.40 = $0.60
$0.60/$3.00 = $0.2
$0.2x100 = 20% decrease

6 0

3 years ago

et y represent the total cost of publishing a book (in dollars). Let x represent the number of copies of the book printed. Suppo

Mice21 [21]

The change in the total cost for each book printed is $10.

The cost to get started ( before any books are printed) is $1200

Step - by -step Explanation

What to find?

• The change in the total cost for each book printed.

,

• The cost to get started ( before any books are printed).

Given:

The given equation is 1200 + 10x = y

where x is the number of xopies of book printed and y is the total cost of publishing the book .

b) To obtain the cost to get started;

Substitute x = 0 into the given equation.

1200 + 10(0) = y

1200 = y

Hence, the cost to get started is $1200

a) To find the cost for each book;

Put x =1 in the given equation.

1200 + 10(1) = y

1210 =y

Change in cost for each book printed is 1210 - 1200 = 10

Hence, the change in the total cost for each book printed is $10.

5 0

1 year ago

Jamaal bounces on a trampoline. His height, as a function of time, is modeled by y = -6x2 + 20x +4

kykrilka [37]

Answer: The function is no linear

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago

Need help on 5. 6. And 7. 7.c is (6+x)-8 7.d is 8-(6+x)

enyata [817]

#7 is A
For # 5 & 6 is there a multiplication sign between the numbers or is supposed to be a power or something else?

7 0

3 years ago