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topjm [15]
3 years ago
10

In a sample of 50 households, the mean number of hours spent on social networking sites during the month of January was 45 hours

. In a much larger study, the standard deviation was determined to be 8 hours. Assume the population standard deviation is the same. Which of the statement below best describes that there is a 95% confidence interval for the mean hours devoted to social networking in January? A. The 95% confidence interval ranges from 8 to 45 hours. B. The 95% confidence interval ranges from 40.13 to 45.78 hours. C. The 95% confidence interval ranges from 43.87 to 46.13 hours. D. The 95% confidence interval ranges from 42.78 to 47.22 hours.
Mathematics
2 answers:
WITCHER [35]3 years ago
6 0

Answer:

D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

Step-by-step explanation:

In a sample of 50 households, the mean number of hours spent on social networking sites during the month of January was 45 hours. In a much larger study, the standard deviation was determined to be 8 hours.

Here,

n = sample size = 50,

μ = mean = 45,

σ = standard deviation = 8,

We know that, confidence interval will be,

=\mu\ \pm\ z\dfrac{\sigma }{\sqrt{n}}

For a confidence interval of 95%, we use z = 1.96, putting the values

=45\ \pm\ 1.96\dfrac{8}{\sqrt{50}}

=42.78,47.22

Darya [45]3 years ago
4 0
<span>D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

To solve the interval, we used the upper and lower limit formulas wherein:
xbar = 45
z = 1.96
s = 8
n = 50</span>
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3 0
3 years ago
PLZ HELP ASAP Geometry help: 2x^2 + 2y^2 - 8x +10y +2=0
Alexxx [7]
Ok so this is conic sectuion
first group x's with x's and y's with y's
then complete the squra with x's and y's


2x^2-8x+2y^2+10y+2=0
2(x^2-4x)+2(y^2+5y)+2=0
take 1/2 of linear coeficient and square
-4/2=-2, (-2)^2=4
5/2=2.5, 2.5^2=6.25
add that and negative inside

2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
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2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0
distribute
2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
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6 0
3 years ago
The measure of angle 1 is 39 degrees. What is the measure of the angle adjacent to angle<br> 1?
Bogdan [553]

Answer:

51

Step-by-step explanation:

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6 0
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laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

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4 0
3 years ago
Help me plz thank you but try to put the right answer
Sedbober [7]

Answer:

Option D is correct.

Step-by-step explanation:

Have a nice day. ;-)

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