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Nikolay [14]
3 years ago
7

Match the terms with their correct definition:

Chemistry
1 answer:
geniusboy [140]3 years ago
7 0
<h2><em>1. A</em></h2><h2><em>3. B</em></h2><h2><em>4. C</em></h2><h2><em>7. E</em></h2><h2><em>5. F</em></h2>
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Easy one! giving brainly if correct​
Dafna1 [17]

Answer: glass is not considered as solute.

Extra's:

A solute is a substance that gets dissolved in a solvent. ... The solutes in air are oxygen, argon, and carbon dioxide gas, as well as water vapour.

Sugar is a solute in the solvent water. Sugar is one of the most soluble solutes in water.

Also solute is a powder that can be dissolved in solvent like water. here baking soda is a solute.

5 0
2 years ago
What number is considered neutral? (On the pH scale)
VMariaS [17]
7 is neutral on the pH scale
4 0
3 years ago
The order of elements in the periodic table is based on the atomic number.
Gnoma [55]
Yes it is for example look at Iodine and Tellurium.
Hope this helps :).
3 0
2 years ago
Temperature is ____ related to the average kinetic energy of a gas.
Nastasia [14]

Answer:

directly

Explanation:

Temperature is defined as the average kinetic energy per particle of a gas, hence temperature and average kinetic energy are directly related meaning that if kinetic energy of a gas increases temperature will also increase.

5 0
3 years ago
Read 2 more answers
An environmental scientist developed a new analytical method for the determination of cadmium (cd^2+) in mussels. To validate th
Anettt [7]

Answer:

The method is accurate  in the calculation of the Cu^+2

Explanation:

As a first step we have to calculate the <u>average concentration </u>of Cu^+2 find it by the method.

\frac{0.782+0.762+0.825+0.838+0.761 }{5} =0.79 ppm

Then we have to find the<u> standard deviation:</u>

s=\sqrt{\frac{1}{N-1}\sum_{i=1}^N(x_i-\bar{x})^2}=0.0359

For the confidence interval we have to use the formula:

μ=Average±\frac{t*s}{\sqrt{n} }

Where:

t=t student constant with 95 % of confidence and 5 data=2.78

μ= 0.79  ±  \frac{2.78*0.0359}{\sqrt{5} }

upper limit:  0.84

lower limit: 0.75

If we compare the limits of the value obtanied by the method (Figure 1 Red line) with the reference material (Figure 1 blue line) we can see that the values obtained by the method are within the values suggested by the reference material. So, it's method is accurate.

7 0
3 years ago
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