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Svetlanka [38]
3 years ago
12

What is buffer solution?

Chemistry
1 answer:
Olenka [21]3 years ago
6 0
A buffer solution is a aqueous solution consisting of a mixture of a weak acid and it conjugate base, or vice versa.
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The store paid 4.50 for a book and sold it for $7.65.what is the profit as a percent of the cost to the store? A. 3. 15% b. 58.8
xeze [42]

Answer: This would be C.) 70%

Explanation:

4 0
3 years ago
In humans, unattached earlobes are dominant over attached earlobes. Which could be the genotype for someone with attached earlob
matrenka [14]
The genotype for some with attached earlobes would be ee because unattached earlobes are dominant(EE or Ee) which means attached would be recessive(ee).
5 0
4 years ago
Read 2 more answers
The mass of .10 moles of iron is:
Stels [109]

Answer:

<em>so mass in gram=560grams</em>

Explanation:

number of moles=10moles

molar mass=56grams/moles

mass in gram of Fe=?

as we know that

number of moles=\frac{mass in gram}{molar mass}

<em>evaluating the formula</em>

<em>number of moles×molar mass=mass in gram</em>

<em>mass in gram=10moles×56grams/moles</em>

<em>mass in gram=560grams</em>

<em>i hope this will help you :)</em>

8 0
4 years ago
Read 2 more answers
One of the reactions in a blast furnace used to reduce iron is shown above. How many grams of Fe2O3 are required to produce 15.5
Salsk061 [2.6K]

Answer : The correct option is, (b) 22.1 g

Solution : Given,

Mass of iron = 15.5 g

Molar mass of iron = 56 g/mole

Molar mass of Fe_2O_3 = 160 g/mole

First we have to calculate the moles of iron.

\text{Moles of Fe}=\frac{\text{Mass of Fe}}{\text{Molar mass of Fe}}=\frac{15.5g}{56g/mole}=0.276moles

Now we have to calculate the moles of Fe_2O_3.

The balanced reaction is,

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2

From the balanced reaction, we conclude that

As, 2 moles of iron obtained from 1 mole of Fe_2O_3

So, 0.276 moles of iron obtained from \frac{0.276}{2}=0.138 mole of Fe_2O_3

Now we have to calculate the mass of Fe_2O_3

\text{Mass of }Fe_2O_3=\text{Moles of }Fe_2O_3\times \text{Molar mass of }Fe_2O_3

\text{Mass of }Fe_2O_3=(0.138mole)\times (160g/mole)=22.08g=22.1g

Therefore, the amount of Fe_2O_3 required are, 22.1 grams.

6 0
3 years ago
If you start with 13 mole H2O and 50 grams of O2 what is the percent yield of H202 if 100 grams of H202 is actually made?
dmitriy555 [2]

Answer:

94.1 %

Explanation:

We firstly determine the equation:

2H₂O + O₂ →  2H₂O₂

2 moles of water react to 1 mol of oxygen in order to produce 2 moles of oxygen peroxide.

We convert the mass of oxygen to moles:50 g . 1mol /32g = 1.56 mol

Certainly oxygen is the limiting reactant.

2 moles of water react to 1 mol of oxygen.

13 moles of water may react to 13/2 = 6.5 moles. (And we only have 1.56)

As we determine the limiting reactant we continue to the products:

1 mol of O₂ can produce 2 moles of H₂O₂

Then 1.56 moles of O₂ will produce (1.56 . 2) = 3.125 moles

We convert the moles to mass: 3.125 mol . 34 g/mol= 106.25 g

That's the 100% yield or it can be called theoretical yield.

Percent yield = (Yield produced / Theoretical yield) . 100

(100g / 106.25 g) . 100 = 94.1 %

3 0
3 years ago
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