Nutrients in a banana
<span>Vitamin B6 – .5 mg
Manganese – .3 mg
Vitamin C – 9 mg <span>
Potassium – 450 mg </span></span>
<span>Dietary Fiber – 3g
Protein – 1 g
Magnesium – 34 mg
Folate – 25.0 mcg </span>
<span>Riboflavin – .1 mg
Niacin – .8 mg
Vitamin A – 81
IU Iron – .3 mg</span>
Answer:
(a) -49.9 kJ/mol;
(b) To the right;
(c) 34.6 kJ/mol
Explanation:
(a) For this reaction, since it's at equilibrium and standard states, we know that we can apply the equation:
Substituting the given variables:
(b) Notice that this reaction is spontaneous, since 
. This means reaction spontaneously proceeds to the right side. Besides, K > 1, this means products dominate over reactants, so reaction proceeds to the right.
(c) Given the expression of the formation constant, we can use the same expression to calculate the reaction quotient at non-standard conditions:
![Q_f = \frac{[Ni(NH_3)_6]^{2+}}{[Ni^{2+}][NH_3]^6} = \frac{0.010}{0.0010\cdot 0.0050^6} = 6.4\cdot 10^{14}](https://tex.z-dn.net/?f=Q_f%20%3D%20%5Cfrac%7B%5BNi%28NH_3%29_6%5D%5E%7B2%2B%7D%7D%7B%5BNi%5E%7B2%2B%7D%5D%5BNH_3%5D%5E6%7D%20%3D%20%5Cfrac%7B0.010%7D%7B0.0010%5Ccdot%200.0050%5E6%7D%20%3D%206.4%5Ccdot%2010%5E%7B14%7D)
Now, notice that 
. In this case, we have an excess of the products, this means reaction will shift to the let left to restore the equilibrium.
Calculate:
Answer:
Explanation: the number of circles in the electronic configuration of an element is represented in the periodic table as the period number that element is situated in. the number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in.
<span>A. insoluble solids in water
</span><span>C. solids of different sizes</span>
