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denpristay [2]
4 years ago
10

H3c6h5o7(aq) + 3nahco3(aq) → 3co2(g) + 3h2o(l) + na3c6h5o7(aq) calculate the number of grams of baking soda (nahco3; molar mass

84.00661 g/mol) that will react with 30.0 ml of 1 m citric acid.
Chemistry
1 answer:
Eduardwww [97]4 years ago
4 0
Determine the number of moles of citric acid.

 n of citric acid = (30 mL)(1 L / 1000 mL)(1 mol/L)
                        = 0.03 mol of citric acid

It is seen in the equation that each mole of citric acid reacts with 3 moles of baking soda.

  n of baking soda = (0.03 mol of citric acid)(3 mols baking soda/1 mol of citric acid)
 
  n of baking soda = 0.09 mol of baking soda
 
          mass of baking soda = (0.09 mol of baking soda)(84.00661 g/mol)
         mass of baking soda = 7.56 g of baking soda

Answer: 7.56 g
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The mass of each WtWt isotope is measured relative to C−12C−12 and tabulated below. Use the mass of C−12C−12 to convert each of
Nadya [2.5K]

The question is incomplete , the complete question is;

The mass of each Wt isotope is measured relative to C-12 and tabulated below. Use the mass of C-12 to convert each of the masses to amu and calculate the atomic mass of Wt.

Wt-296  =  24.6622

Answer:

The atomic mass of Wt-296 is 195.9464 amu.

Explanation:

1 amu is defined as 1 by twelfth of the carbon-12 mass.

Mass of an isotope Wt-296 = 24.6622

Mass of an isotope Wt-296 in amu = M

M\times \frac{1}{12 amu}=24.6622

M=24.6622\times 12 amu=295.9464 amu

The atomic mass of Wt-296 is 195.9464 amu.

8 0
3 years ago
A typical neon light contains neon gas mixed with argon gas.  If the total
devlian [24]
The partial pressure of argon is:

1.63-0.71=  0.92 atm


5 0
4 years ago
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What would the mass be for 500 ml of water?
Margarita [4]
The density of water is about 1.00 g/ml, so 500 ml of  water is about 500 g 
4 0
4 years ago
The melting and freezing points of a substance are the same temperature.<br> a. True<br> b. False
kow [346]
That's false. A melting point is hot/warm, while the freezing point is cold.
7 0
4 years ago
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A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.
Eddi Din [679]

Answer:

17.09g/L

Explanation:

Density = total mass of elements/ volume

We need to find the mass of each mixture constituents using their molar mass:

mole = mass/molar mass

For Neon (Ne) which contains 0.650mol;

0.650 = mass/20.18

mass = 0.650 × 20.18

mass = 13.12g

For Krypton (Kr) which contains 0.321mol;

0.321 = mass/83.79

mass = 0.321 × 83.79

mass = 26.89g

For Xenon (Xe) which contains 0.190mol;

0.190 = mass/131.3

mass = 0.190 × 131.3

mass = 24.95g

Total mass = 13.12g + 26.89g + 24.95g = 64.96g

Density = total mass / volume

Density = 64.96g / 3.80L

Density of the mixture = 17.09g/L

7 0
3 years ago
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