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NNADVOKAT [17]
3 years ago
9

Vertex of -2(x+3)^2+7

Mathematics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

The vertex is (-3, 7)

Step-by-step explanation:

As the equation is already in 'rectangular form), to work out the vertex, we can just compare this equation to that of the standard parabola y = x^2, and in particular, consider how it has been translated:

the (x+3) part moves the graph the the left 3 (i.e in the negative direction), while the +7 moves the graph up 7.

So as the vertex of the simple parabola y = x^2 is (0,0), the vertex of this graph is just (-3,7).

Note that the -2 at the front doesn't impact this vertex - this -2 just changes the 'scale' of the parabola (i.e makes it more narrow, and also turns it upside down as it's a negative number).

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y = 10(20) + 10
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3 years ago
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goblinko [34]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
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In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.
Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

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j = \sqrt{99.45}

j = 9.97

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\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}

{9.97 \times    Sin (L ) = (2.7 \times Sin \ 43)

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2 years ago
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4. 80

Step-by-step explanation:

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2 years ago
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eduard

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Step-by-step explanation:

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