When iron rusts in air, iron(III) oxide is produced.
1 answer:
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Answer:
The heat lost by the water 3.8 KJ
The heat gain by ice = 228.76 J
The heat required to melt the ice = 3340 J
Explanation:
Mass of ice cube = 10 gm
Initial temperature of ice cube = 0 °c
Mass of water = 100 gm
Initial temperature of water = 20 °c
Final temperature of mixture = 10.93 °c
(a). Total heat lost by the water
(
-
)
⇒ 100 × 4.184 (20 - 10.93)
⇒ 3.8 KJ
This is the heat lost by the water.
(b). Heat gained by the ice cube =
⇒ = 10 × 2.093 × ( 10.93 - 0)
⇒ = 228.76 J
This is the heat gain by ice.
(C). Heat required to melt the ice =
× Latent Heat
⇒ = 10 × 334
⇒ = 3340 J
This is the heat required to melt the ice.