According to the activity series, which one of the following reactions will occur?

How many moles of sodium carbonate are contained by 57.3g of sodium carbonate

Lady_Fox [76]

Answer:

$\boxed {\boxed {\sf 0.541 \ mol \ Na_2CO_3}}$

Explanation:

We are asked to find how many moles of sodium carbonate are in 57.3 grams of the substance.

Carbonate is CO₃ and has an oxidation number of -2. Sodium is Na and has an oxidation number of +1. There must be 2 moles of sodium so the charge of the sodium balances the charge of the carbonate. The formula is Na₂CO₃.

We will convert grams to moles using the molar mass or the mass of 1 mole of a substance. They are found on the Periodic Table as the atomic masses, but the units are grams per mole instead of atomic mass units. Look up the molar masses of the individual elements.

Na: 22.9897693 g/mol
C: 12.011 g/mol
O: 15.999 g/mol

Remember the formula contains subscripts. There are multiple moles of some elements in 1 mole of the compound. We multiply the element's molar mass by the subscript after it, then add everything together.

Na₂ = 22.9897693 * 2= 45.9795386 g/mol
O₃ = 15.999 * 3= 47.997 g/mol
Na₂CO₃= 45.9795386 + 12.011 + 47.997 =105.9875386 g/mol

We will convert using dimensional analysis. Set up a ratio using the molar mass.

$\frac {105.9875386 \ g \ Na_2CO_3}{1 \ mol \ Na_2CO_3}$

We are converting 57.3 grams to moles, so we multiply by this value.

$57.3 \ g \ Na_2CO_3} *\frac {105.9875386 \ g \ Na_2CO_3}{1 \ mol \ Na_2CO_3}$

Flip the ratio so the units of grams of sodium carbonate cancel.

$57.3 \ g \ Na_2CO_3} *\frac {1 \ mol \ Na_2CO_3}{105.9875386 \ g \ Na_2CO_3}$

$57.3 } *\frac {1 \ mol \ Na_2CO_3}{105.9875386 }$

$\frac {57.3 }{105.9875386 } \ mol \ Na_2CO_3$

$0.5406295944 \ mol \ Na_2CO_3$

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place to the right tells us to round the 0 up to a 1.

$0.541 \ mol \ Na_2CO_3$

There are approximately <u>0.541 moles of sodium carbonate</u> in 57.3 grams.

6 0

2 years ago

Kenya has a pile of salt on the counter. She uses a pinch of it for a meal. Which of the following physical properties of the sa

AlladinOne [14]

The following choices are all extensive properties, meaning they do not change with the amount of the substance. Although, 3 of the properties, namely, density, solubility and thermal conductivity are temperature-dependent. Since the problem did not mention of heating, let's assume Kenya just used it directly for her meal. Among the choices, I think shape would change. Once you place it in the meal, you can no longer pinpoint the salt because it's shape has been changed.

7 0

2 years ago

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How does an atom become a positively charged ion? by gaining one or more electrons by gaining one or more neutrons by losing one

erma4kov [3.2K]

By losing one or more electrons

4 0

3 years ago

Sodium bicarbonate is sometimes used to neutralize acid spills. If 2.0 L of 1.0 M H2SO4 is spilled, what mass of sodium bicarbon

UkoKoshka [18]

Answer:

168.0 g

Explanation:

First thing, write a balanced chemical equation:

$H_{2}SO_{4}+ 2NaHCO_{3} ----> Na_{2}SO_{4} + 2H_{2}O+2CO_{2}$

n(H2SO4) = concentration * volume

= 1.0 M * 2.0 L

= 2.0 mol

According to the balanced equation, 1 mol of acid requires 2 mol of sodium bicarbonate. This means that 2 mol of acid requires 2 mol of sodium bicarbonate. What mass of sodium bicarbonate is this?

mass (NaHCO3) = number of moles * molar mass

= 2.0 mol * 84.0065 g/mol

= 168.0 g

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2 years ago

What are the three properties of gas

MArishka [77]

Gas water and ice i think bro

4 0

3 years ago

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