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There is some missing info. I think this is the complete question.
<em>A student dissolves 4.6 g of glucose in 500 mL of a solvent with a density of 0.87 g/mL. The student notices that the volume of the solvent does not change when the glucose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.</em>
Step 1: Calculate the moles of glucose (solute)
The molar mass of glucose is 180.16 g/mol.
4.6 g × 1 mol/180.16 g = 0.026 mol
Step 2: Calculate the molarity of the solution
0.026 moles of glucose are dissolved in 500 mL (0.500 L) of solution. We will use the definition of molarity.
M = moles of solute / liters of solution
M = 0.026 mol / 0.500 L = 0.052 M
Step 3: Calculate the mass corresponding to 500 mL of the solvent
In order to determine the amount of how many kilograms to order, the teacher will need to find out the total mass of clay required by the students and then the teacher will have to convert the total mass to the units required for the purchase.
The teacher would have to find out how many milligrams make one kilogram as follows