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ivanzaharov [21]
3 years ago
9

How many bits are needed to represent the decimal number 200?

Mathematics
1 answer:
mina [271]3 years ago
7 0
Log 2 200 = In 200 ã• In 2 = 7.6... â need 8 bits. If a signed number is being stored, then 9 bits would be needed as one as one would be needed to indicate the sign of the number.

8 (assuming unsigned numbers - i.e., you don’t reserve a bit for the sign.
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5 pointsWhich is the image of vertex Lafter the triangle is rotated 180 degrees about the origin?
Anastasy [175]

The image of vertex L after the triangle is rotated 180 degrees about the origin= (-2, -1).

Option B.

First let's stae the the original location of the figure on the graph.

From the graph:

L (2, 1)

W(1, -3)

O (-1, -2)

A rotation of 180 degrees about the origin will change the x and y axis of each location to the opposite of those numbers;

Positive numbers becomes negative and negative numbers becomes positive.

The new location for L = L'

L' = (-2, -1)

The new location for W = W'

W' = (-1, 3)

The new location for O = O'

O' = (1, 2)

Hence, the image of vertex L after the triangle is rotated 180 degrees about the origin= (-2, -1).

Option B.

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1 year ago
In circle N with the measure of arc MP= 98°, find mZMNP.<br> P<br> M<br> N
aliya0001 [1]

Answer:Use the equation to find the arc length. KCJ or 105. is about 13.74 centimeters.

Step-by-step explanation: Use the equation to find the arc length. KCJ or 105. is about 13.74 centimeters.

4 0
3 years ago
I need help on all of these plz
shusha [124]
Can't read the top questions mate !
8 0
3 years ago
3 gallons of paint cover 900 square feet. How many gallons will cover 300<br> square feet?
SVEN [57.7K]

Answer:

1 gallon

Step-by-step explanation:

Since the relationship is direct, meaning as the number of square feet decreases, the number of gallons also decreases.

3:900 = x:300

solution:

3(300) = 900x

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3 years ago
Read 2 more answers
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vladimir1956 [14]

Step-by-step explanation:

The answer for third is D, you have multiple choice in fourth which I can't see at all...

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