Answer:
y = 1/12 (x − 5)²
Step-by-step explanation:
We can solve this graphically without doing calculations.
The y component of the focus is y = 3. Since this is above the directrix, we know this is an upward facing parabola, so it must have a positive coefficient. That narrows the possible answers to A and C.
The x component of the focus is x = 5. Since this is above the vertex, we know the x component of the vertex is also x = 5.
So the answer is A. y = 1/12 (x−5)².
But let's say this wasn't a multiple choice question and we needed to do calculations. The equation of a parabola is:
y = 1/(4p) (x − h)² + k
where (h, k) is the vertex and p is the distance from the vertex to the focus.
The vertex is halfway between the focus and the directrix. So p is half the difference of the y components:
p = (3 − (-3)) / 2
p = 3
k, the y component of the vertex, is the average:
k = (3 + (-3)) / 2
k = 0
And h, the x component of the vertex, is the same as the focus:
h = 5
So:
y = 1/(4×3) (x − 5)² + 0
y = 1/12 (x − 5)²
The answer to your question is:
+4
-4, -3, -2, -1, 0, 1, 2, 3, 4
28, because when you divide you get about 28. good luck!
Answer:
20. 
22. 
24. 
Step-by-step explanation:
20. 
The GCF is x, so you group it out of the equation first.
Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.
The two numbers would be -6 and 8. You then differentiate the squares.
22. 
The GCF is 2, so you must group it out.
Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.
The two numbers would be 1 and 4. Finally, differentiate the squares.
24. 
The GCF is 5m, so you must group it out.
Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.
The two numbers would be -1 and 7. Finally, differentiate the squares.
Answer:
13 and 16
Step-by-step explanation:
let the 2 parts be x and y, then
x + y = 29 → (1) and
x² + y² = 425 → (2)
From (1) → x = 29 - y → (3)
substitute x = 29 - y into (2)
(29 - y)² + y² = 425 ( expand factor )
841 - 58y + y² + y² = 425 ( rearrange into standard form )
2y² - 58y + 416 = 0 ← in standard quadratic form
divide all terms by 2
y² - 29y + 208 = 0
Consider the factors of 208 which sum to - 29
These are - 13 and - 16, hence
(y - 13)(y - 16) = 0
equate each factor to zero and solve for y
y - 13 = 0 ⇒ y = 13
y - 16 = 0 ⇒ y = 16
substitute these values into (3)
x = 29 - 13 = 16 and x = 29 - 16 = 13
The 2 parts are 13 and 16
