Answer:
d, e
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b
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In this case, it means the product is ...
(6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36
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The 6 without an exponent is equivalent to 6^1, an exponent of 1.
The sum of the exponents is -2.
Add the exponents to simplify the expression.
The value of the expression is 1/36.
An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).
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Only the last two choices, d and e, apply.
2+2-1 that's three quick maths.
x > 7 x < 10
7 o---------------------o 10
This is not an empty set. x contains all of the values between 7 and 10.
FIRST. find the factors:
X=-5 --> (X + 5) = 0
x = 1--> (X - 1) = 0
x =3 --> (x - 3) = 0
3
NEXT, multiply all the factors:
(x + 5) (x - 1) (x - 3) = 0
-> X3 + x2 - 17x +15 = 0
-> f(x) = x3 + x2 - 17x +15 or
y=x3 + x2
17x + 15
Answer:
$40
Step-by-step explanation:
Divide.
$800 / 20 hrs.
= $40
