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olchik [2.2K]
4 years ago
15

Please help :D <3. Do not understand this one.

Mathematics
1 answer:
Shtirlitz [24]4 years ago
8 0
Sorry for my messy handwriting but this is the answer

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I don’t understand” please help!!<br> It’s due tomorrow
oksian1 [2.3K]

Answer: The answer to the first question is C(20%)

Step-by-step explanation: 1. you need to find the absolute decrease which is subtracting 350-280= 70.

2. now you need to find the percent decrease which is dividing the absolute decrease by the whole price.. so.. 70/350= .20

3. now just multiply .20 *100 = 20%

8 0
4 years ago
Read 2 more answers
bruce is playing with a set of base-ten blocks. he has 65 ten-blocks and 7 one-blocks. what is the value of his blocks
Oksi-84 [34.3K]
The 65 tens blocks can be solved by doing 65x10 which is 650.  the 7 ones blocks can be solved by 1x7  which is 7 so you then add up 650 and 7 to get a grand total of 657
5 0
4 years ago
Concentric circles have radil of 4 cm and 8 cm. What is the probability that a
monitta

The probability that a  grain of rice dropped onto the circles at random lands outside the circle with the  4-cm radius and inside the circle with a radius of 8 cm is \frac{3}{4} or 75%.

Step-by-step explanation:

Step 1:

First, we need to calculate the areas of both circles.

The area of a circle = \pi r^{2} where r is the radius of the circle.

The inner-circle has a radius of 4 cm.

The area of the inner circle= \pi (4^{2})= 3.1415(16) = 50.264.

The outer circle has an inner radius of 4 cm and an outer radius of 8 cm.

So its area is \pi (R^{2} -r^{2} ) where R is the outer radius and r is the inner radius.

The area of the outer circle= \pi (8^{2} -4^{2})= 3.1415(64-16).

3.1415(48) = 150.792.

So the inner circle has an area of 50.264 square cm and the outer circle has an area of 150.792 square cm.

Step 2:

To find the probability of an event we divide the number of favorable outcomes by the total number of outcomes.

The total number of outcomes is the area of the entire circle

= 50.264+150.792 = 201.056 square cm.

The number of favorable outcomes is the area of the outer circle i.e. 150.792 square cm.

The probability of the rice falling in the outer circle =\frac{150.792}{201.056} = \frac{3}{4} = 75 \%.

7 0
3 years ago
Please help me ughhh
Rudik [331]

If there are outliers, IQR is a better measure of the spread of data than range. The range will include the outliers, and make the data appear to have many more terms of a greater/lesser value than it has in reality. IQR shows the middle 50%, which (usually) doesn't contain outliers, so the majority of the data spread would be shown by IQR in a data sample with a significant amount of outliers. If your measure of the spread of data contains outliers, then the measure isn't accurate.

4 0
3 years ago
4x+3 =23<br>2x - 10 = -32<br>- 4x + 1 = -27<br>6x - 2 = -20​
Scrat [10]

Answer:

1)x = 5

2)× = -11

3)x = 7

4)x = 3.66

7 0
3 years ago
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