What you can do in this case is a rule of three to determine the length of each bow.
We have then:
1/4 ---> 2
x ------> 1
Clearing x we have:
x = (1/2) * (1/4)
x = 1/8
Answer:
the length of ribbon in each bow is
x = 1/8
Equivalently:
x = (1/4) / 2
Option 3
Answer:
-20⅖
Step-by-step explanation:
5⅔(-3.6)
(17/3)(-3.6)
17(-3.6/3)
17(-1.2)
-20.4
-20 ⅖
Answer: 3
Step-by-step explanation:
Let E be the event of that student pierces ear and N be the event of that student pierces nose.
Given: 

For any two event A and B, we have

Similarly , 

Hence, 3 students have piercings both on their ears and their noses.
Answer:
a) For this case we can use the definition of weighted average given by:

And if we replace the values given we have:

b) 
c) 
Step-by-step explanation:
Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.
a) What is the mean for the combined set if both of the original samples have n=4 scores
"
For this case we can use the definition of weighted average given by:

And if we replace the values given we have:

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5
Using the definition we have:

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3
Using the definition we have:

“C” Os the correct answer