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Vinvika [58]
3 years ago
10

One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is t

he mean for the combined set if both of the original samples have scores
Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0

Answer:

a) For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) M = \frac{8*3 + 16*5}{3+5}= 13

c) M = \frac{8*5 + 16*3}{5+3}= 11

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

M = \frac{8*3 + 16*5}{3+5}= 13

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

M = \frac{8*5 + 16*3}{5+3}= 11

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1 year ago
Help plz find the equation​
tatiyna

                                              Question # 1

Step-by-step Explanation:

Given

\frac{1}{2}\div \frac{2}{3}

solving

\frac{1}{2}\div \frac{2}{3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{1}{2}\times \frac{3}{2}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{1\times \:3}{2\times \:2}

\mathrm{Multiply\:the\:numbers:}\:1\times \:3=3

=\frac{3}{2\times \:2}

\mathrm{Multiply\:the\:numbers:}\:2\times \:2=4

=\frac{3}{4}

Therefore, completing the blanks:

\frac{1}{2}\div \frac{2}{3}=\frac{1}{2}\times \frac{3}{2}=\frac{3}{4}

                                             Question # 3

Step-by-step Explanation:

Given

\frac{2}{5}\div \frac{3}{4}

solving

\frac{2}{5}\div \frac{3}{4}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{2}{5}\times \frac{4}{3}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{2\times \:4}{5\times \:3}

\mathrm{Multiply\:the\:numbers:}\:2\times \:4=8

=\frac{8}{5\times \:3}

\mathrm{Multiply\:the\:numbers:}\:5\times \:3=15

=\frac{8}{15}

Therefore, completing the blanks:

\frac{2}{5}\div \frac{3}{4}=\frac{2}{5}\times \:\frac{4}{3}=\frac{8}{15}

                                                Question # 5

Step-by-step Explanation:

Given

\frac{3}{4}\div \frac{5}{7}

solving

\frac{3}{4}\div \frac{5}{7}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{3}{4}\times \frac{7}{5}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{3\times \:7}{4\times \:5}

\mathrm{Multiply\:the\:numbers:}\:3\times \:7=21

=\frac{21}{4\times \:5}

\mathrm{Multiply\:the\:numbers:}\:4\times \:5=20

=\frac{21}{20}

Therefore, completing the blanks:

\frac{3}{4}\div \frac{5}{7}=\frac{3}{4}\times \:\frac{7}{5}=\frac{21}{20}

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