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Molodets [167]
3 years ago
12

Question 4 of 15

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0
“C” Os the correct answer
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Dennis wants to buy a card for his wife. Dennis calculates the amount of the card as $4.50. The actual price of a card is $4. Wh
Alex17521 [72]

Answer:

12.5%

Step-by-step explanation:

$4.50-$4/$4 x 100%

0.5/4x100%

50/4= 25/2 = 12.5%

8 0
3 years ago
PLEASE HURRY!!!
RoseWind [281]
 terms is x first then  terms in y and constant after the equals

Its C
4 0
4 years ago
Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!
vekshin1

Answer:

2.  3.913 kg (3 dp)

3.  light cream

4.  240 CoffeeStops

5.  7 CoffeeStops per square mile

6.  2,861 cups of coffee each day

Step-by-step explanation:

Given:

  • Skim milk density at 20 °C = 1.033 kg/l
  • Light cream density at 20 °C = 1.012 kg/l
  • 1 liter = 0.264 gallons

<u>Question 2</u>

\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

---------------------------------------------------------------------------------------------

<u>Question 3</u>

Given:

  • Volume of liquid = 9 liters
  • Mass of liquid = 9.108 kg

\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

<u>Question 4</u>

Given:

  • 15 CoffeeStops per 100,000 people
  • Population of Manhattan ≈ 1,602,000 people

\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}

Therefore, there are 240 CoffeeStops.

---------------------------------------------------------------------------------------------

<u>Question 5</u>

Given

  • Manhattan ≈ 34 square miles

\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

<u>Question 6</u>

Given:

  • Each person buys 3 cups of coffee per week

\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}

\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

7 0
2 years ago
Help is very much needed :)
ioda

Answer:

6

Step-by-step explanation:

10/5 ×/3 multiply 10×3 and than divide by 5

or another way start with multiplying 5 and n equaling 5n=

than 10× 3= 30 so you're left with 5n=30 divied 30 by 5 equalling 6

so x=6

3 0
3 years ago
3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu
djverab [1.8K]

Answer:

Probability distribution for x:

P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}

So, we have this probabilty distribution for x:

P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\

7 0
3 years ago
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