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butalik [34]
3 years ago
15

The sun is about 93 * 10^6 miles from earth.What is this distance written as a whole number?

Mathematics
2 answers:
Sergio039 [100]3 years ago
8 0
93,000,000

93 \times 10 ^{6}  = 93000000
svet-max [94.6K]3 years ago
5 0

Multiplication time!



10^6 = 1,000,000


93 × 1,000,000 = 93,000,000


Hope this helps!!!

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Darius created a factor tree and wrote the prime factorization of 60 shown here.
UkoKoshka [18]

Answer: he needs to finish factoring the 4s.

Step-by-step explanation:

4x15 is 60, so that is right, 3x5 is 15, so that’s is right, 2x2 is 4, so that is right, but he didn’t finish factoring. 1x1 is 2, so he should have 1 and 1 coming from each 2 on the tree. Hope this helps.

6 0
3 years ago
The low temperature last week in Iceland was-2.25. The low temperature this week was 1.25. What was the change in temperature fr
viktelen [127]

Answer:

The change in temperature from last week to this week=3.5

Step-by-step explanation:

To get the change in temperature from last week to this week, we need to take last week's temperature and subtract it from this week's temperature.

For example;

Change in temperature=This week's temperature-last week's temperature

where;

This week's temperature=-2.25

last week's temperature=1.25

replacing;

Change in temperature=(1.25)-(-2.25)=1.25+2.25=3.5

The change in temperature from last week to this week=3.5

6 0
3 years ago
LaTasha was presented with the following data set and argued that there was no correlation between x and y. Is LaTasha correct?
andrezito [222]

Answer:

LaTasha is correct. There is no correlation between x and y. The slope of the line of best fit is zero, which shows that there is no negative or positive correlation.

8 0
3 years ago
Read 2 more answers
How do I simplify 1/-5z^-5?
belka [17]
\bf \cfrac{1}{-5z^{-5}}\\\\
-------------------------\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
%  negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\
-------------------------\\\\
thus


\bf -\cfrac{1}{5}\cdot \cfrac{1}{z^{-5}}\implies -\cfrac{1}{5}\cdot \cfrac{1}{\frac{1}{z^5}}\implies -\cfrac{1}{5}\cdot \cfrac{\frac{1}{1}}{\frac{1}{z^5}}\implies -
\cfrac{1}{5}\cdot \cfrac{1}{1}\cdot \cfrac{z^5}{1}
\\\\\\
-\cfrac{z^5}{5}
3 0
3 years ago
Can you help me with this question?
kirill [66]

Yes

Hope this helps                          

5 0
3 years ago
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