Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer & Step-by-step explanation:
It increased by 10 each year
Year 1 of 8: 70
Year 2 of 8: 80
Year 3 of 8: 90
Year 4 of 8: 100
Year 5 of 8: 110
Year 6 of 8: 120
Year 7 of 8: 130
Year 8 of 8 (Final Year): 140
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<u><em>Hope this helps!!! :)</em></u>
Answer:
16
Step-by-step explanation:
I think so.
Ok, so you have your equation, 5·x+5-(5x+25).
First, do the prathases, so you have, 5x+5-5x-25.(5·x also means 5x)
Now, you need to combine like terms, and through that the xs cancel out, so you are left with -20 as you answer.
