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olasank [31]
3 years ago
13

George worked on his science project for a total of 2 2/3 hours. He worked on it for 5/12 hour on Monday and 9/12 hour on Tuesda

y. He finished the project on Wednesday. How long did George work on his project on Wednesday?
Mathematics
1 answer:
dusya [7]3 years ago
7 0
The answer is 1 1/2. To find it you first add 9/12 and 5/12 which equals 14/12 then you make it a mixed fraction which is 1 2/12 which can simplify to 1 1/6. Next you make the denominator of 2/3 and 1/6 equal, so you multiply 2/3 by 2 and you get 4/6 so you now have 2 4/6 and 1 1/6, now you subtract them both which is 1 3/6 which simplified is 1 1/2
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2(5-8x-9x)+4(7x+7)=14
xenn [34]

Step-by-step explanation:

if you are solving for X' it is X=4

8 0
3 years ago
John is twice as old as his son. In 42 years, the ratio of their ages will be 4:3. What is the son's current age?
dsp73

Answer: Jhon is 42 years old, and his son is 21 years old.

Step-by-step explanation:

Let's define:

J = John's age

S = Age of the son.

We know that:

"John is twice as old as his son"

J = 2*S

"In 42 years, the ratio of their ages will be 4:3. What is the son's current age?"

In 42, their ages will be:

J + 42 and S + 42.

And the ratio 4:3 means that:

(J + 42) = (4/3)*(S + 42)

Then we have the system of equations:

J = 2*S

(J + 42) = (4/3)*(S + 42)

To solve it we can first replace the first equation into the second one, to get:

(2*S + 42) = (4/3)*(S + 42)

2*S  - (4/3)*S = (4/3)*42 - 42

S*(6/3 - 4/3) = (1/3)*42

S*(2/3) = (1/3)*42

S = (3/2)*(1/3)*42 = 21.

And we can find Jonh's age if we use the first equation:

J = 2*S = 2*21 = 42

Jhon is 42 years old, and his son is 21 years old.

8 0
3 years ago
The area of a rectangle is 228 sq feet if the length of rectangle is 12 feet what would be the width of the rectangle
zysi [14]
Well you do 228/12 to find your answer and that is 19 and to check you do 12*19=228
8 0
3 years ago
[EXTENDED RESPONSE SHOW ALL WORK.]
Lapatulllka [165]
A.)     the greatest amount of boxes would probably be 8
B.)     the amount of cars would be 5 and the airplanes would be 3 
4 0
3 years ago
Solve each system by substitution. -5x + 3y = 3 and -4x + y = 1
taurus [48]

\left\{\begin{array}{ccc}-5x+3y=3\\-4x+y=1&|\text{add 4x to both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}-5x+3y=3\\y=4x+1&(*)\end{array}\right\\\\\text{Substitute }\ (*)\ \text{to the first equation}\\\\-5x+3(4x+1)=3\qquad\text{use distributive property}\\\\-5x+(3)(4x)+(3)(1)=3\\\\-5x+12x+3=3\qquad\text{subtract 3 from both sides}\\\\7x=0\qquad\text{divide both sides by (-5)}\\\\\boxed{x=0}\\\\\text{Substitute the value of x to}\ (*):\\\\y=4(0)+1\\y=0+1\\\boxed{y=1}\\\\Answer:\ x=0\ and\ y=1.

5 0
3 years ago
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