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ale4655 [162]
2 years ago
13

Which equation represents the linear relationship shown on the graph below?

Mathematics
1 answer:
jek_recluse [69]2 years ago
4 0

To find the linear relationship we need

  • two points on the line: (0,3), (2,4)
  • and the slope = \frac{y2-y1}{x2-x1} =\frac{4-3}{2-0} =\frac{1}{2}

Now lets put any one point on the line such as (0,3) and the slope into the point-slope form:

      y - 3 = (\frac{1}{2} )(x-0)\\y = \frac{1}{2}x + 3

Hope that helps!

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-g+2(3+g)=-4(g+1) answer please?
RideAnS [48]

Answer:

3+g=- 134

Step-by-step explanation:

5 0
3 years ago
What is 4 divided by 6 + 89 - 34 -89 +190
saw5 [17]
4/(6+89-34-89+190)
=4/162
=2/81
That's your answer.
5 0
3 years ago
Read 2 more answers
The baseball coach bought 8 new baseballs for $3 each. The basketball coach bought 6 new basketballs for $11 each. How much more
tia_tia [17]

Answer:

$42 more.

Step-by-step explanation:

Baseball: 8(3) = $24

Basketball: 6(11) = $66

66 - 24 = $42

8 0
3 years ago
Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
The dataset Restaurant Tips contains data recorded from 157 restaurant bills at a bistro in New York over a two week period and
xz_007 [3.2K]

Answer: ($3.532, $4.166)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.90=0.10

Critical value : z_{\alpha/2}=1.645

Sample size : n= 157

Sample mean : \overline{x}=\$\ 3.849

Standard deviation : \sigma= \$\ 2.421

The confidence interval for population mean is given by :_

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

\text{i.e. }\$\ 3.849\pm (1.64)\dfrac{2.421}{\sqrt{157}}\\\\\approx\$\ 3.849\pm0.317\\\\=(\$\ 3.849-0.317,\$\ 3.849+0.317)=(\$\ 3.532,\$\ 4.166)

Hence, the 0% confidence interval for the average tip given at this restaurant = ($3.532, $4.166)

5 0
3 years ago
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