X-2 for x=-3
-3-2=-5, add dem negatives
7y-3°=3y+13°
7y-3y= 13°+3°
4y= 16°
y=4°
Substitute y
7(4)-3°= 25°
3(4)+13=25°
180°-25°-25°=130°
2(2x+3)°+130°=180°
4x+136°=180°
4x=44°
x=11°
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer:
Step-by-step explanation:
Neutron: has mass and no charge
Protons: has mass and a positive charge
Answer:
<h2>
168°</h2>
Option A is the correct option
Step-by-step explanation:
Since, we know that angle at center is double that of the circumference.
JL = 2 × 84°
calculate the product
= 168°
Hope this helps..
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