Question

Show that (x+1) is a factor of f(x)=19x^42+18x-1

Answer 1

Answer:

see explanation

Step-by-step explanation:

If (x + 1) is a factor then f(- 1) = 0

f(- 1) = 19$(-1)^{42}$ + 18(- 1) - 1 = 19 - 18 - 1 = 0

Thus (x + 1) is a factor of f(x)