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Gemiola [76]
3 years ago
13

18. Which number rounds to 0.94 when rounded to the nearesthundredth?

Mathematics
2 answers:
damaskus [11]3 years ago
8 0
I think its 0.9 but im not sure...
Temka [501]3 years ago
5 0
.94 because .9<u>4</u> is the hundredth place.... so unless there are other numbers added on to it.
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Lunna [17]
Well what’s the base and what’s the height and then times then
8 0
3 years ago
NEED DESPERATELY. PLEASE!!! A BIG REWARD IS AT STAKE. BRAINLIEST WILL BE GIVEN. (Keep out for more problems with rewards from me
Rom4ik [11]

Answer:

My total savings was = $58.33

Step-by-step explanation:

Given:

12% of my savings was = $7.00

To find my total savings.

Solution:

Let the total savings in dollars be = x

12% of the total savings will be  = 12\%\ of\ x

12% of my savings was = $7.00

So, we have:

12\%\ of\ x=7

0.12x=7

Solving for x to get my total savings.

Dividing both sides by 0.12

\frac{0.12x}{0.12}=\frac{7}{0.12}

∴ x=58.33

Thus, my total savings was = $58.33

7 0
3 years ago
sam goes to the market to buy a hamburger for cookout. he buys 3 3/4 pounds if a hamburger. how many 1/4 pound patties can he ma
Alexandra [31]
3 3/4÷ 1/4
15/4÷1/4
15/4÷4/1
15*4=60
4*1=4
60/4=15
15 times 1/4 can fit into 3 3/4.
7 0
3 years ago
What is the slope of the line threw (-9,6) and (-3, 9)
DerKrebs [107]

Slope = (y2-y1)/(x2 - x1)


Slope = (9 - 6)/(-3- (-9)) = 3/6 = 1/2


Answer: 1/2

4 0
2 years ago
Read 2 more answers
Mario invests 1,500 in a savings account that earns 2% interest a year. He also plans to set aside $50 cash a month. A:2100(1.02
Sedbober [7]

Answer:

<em>1500(1.02)^x  +   600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere

Step-by-step explanation:

x is in years

Let's just think about the investment of 1500 in an account earning 2% per year.

Before the years even start, you are at 1500 ( present value).

The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).

The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).

We keep multiplying factors of (1.02) each time.

So for year x, you would have saved 1500(1.02)^x.

Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year.  12(50)=600.  

So the first year you would have 600.

The second year you would have 600(2) or 1200.

The third year you would have 600(3) or 1800.

Let's put this together:

1500(1.02)^x  +   600x

4 0
3 years ago
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