Answer:
-90cm
Explanation:
u=−30cm and magnification m=(−v/u)=−3 so v=(3u)image is real so m should be negative v should be negative so v=−90cm
putting the above values of v and u in the Mirror equation,
f1=u1+v1
we get focal length f=−22.5cm and image position v=−90cm
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Answer:
1.56 J
Explanation:
The potential energy only depends on the vertical height from the ground level.
We consider the ground level to have zero P.E.
So when it is 2 m above the ground level,
P.E. = mgh
= 0.078×10×2
= 1.56 J
<h3><u>Answer;</u></h3>
C. 228 Joules
<h3><u>Explanation;</u></h3>
<em><u>Efficiency of a machine is the energy or work output, divided by the energy or work input, and expressed as a percentage. </u></em> An ideal machine would have an efficiency of 100%.
Efficiency = (work output/work input) × 100%
work input = 350 joules, efficiency = 65.1%
Work output = 350 j × 65.1/100
= 227.85
<u>≈ 228 Joules</u>
Answer:
I beleive its B
Explanation:
If not then A but I'm positive its B