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3 years ago

Use the periodic table from the lesson to answer the following question.

Physics

2 answers:

kodGreya [7K]3 years ago

7 0

Answer:

18.99u or 19u

Explanation:

Mass number=No of protons+No of neutrons

$\\ \sf\longmapsto 9+10$

$\\ \sf\longmapsto 19u$

Fluorine has atomic number=9
The Electronic configuration is given by

$\\ \sf\longmapsto 1s^22s^22p^5$

lys-0071 [83]3 years ago

4 0

Answer:

$mass \: number = no. \: of \: protons \\ + no. \: of \: neutrons \\ = 9 + 10 = 19u. \\ \\ 1s {}^{2} 2s {}^{2} 2p {}^{5.}$

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Of all the planets, which is the most different from the others? Explain.

Alenkinab [10]

Answer: VENUS

Explanation:

Venus tiene una lenta rotación retrógrada, lo que significa que gira de este a oeste, en lugar de hacerlo de oeste a este como lo hacen la mayoría de los demás planetas mayores (Urano también tiene una rotación retrógrada, aunque el eje de rotación de Urano, inclinado 97.86°, prácticamente descansa sobre el plano.

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4 years ago

Read 2 more answers

Before railroad were invented, goods often traveled along canals, with mules pulling barges from the bank. If a mule is exerting

morpeh [17]

Answer:

W = 112.76MJ

Explanation:

the work is:

$W = F_xD$

where $F_x$ is the force executed in the direction of the displacement and the d the displacement.

so:

W = 12000Ncos(20)(10000)

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W = 112.76MJ

8 0

3 years ago

You drop a rock off the top of a building. It takes 3.4 s to hit the ground. What is the velocity at impact (final velocity)? I

SCORPION-xisa [38]

-- The acceleration of gravity (on Earth) is 9.8 m/s².

-- That means that during every second an object falls,
it adds 9.8 m/s of speed.

Now ! If it adds 9.8 m/s of speed every second, then
how fast is it falling at the end of 3.4 seconds ?

This is as close as I can bring you to the answer
without dropping it at your feet, or handing it to you
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3 years ago

The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 7.00 s, at which time it

Schach [20]

Answer:

The tub of the washer does 37.5 revolutions while it is in motion.

Explanation:

At first we assume that the tub accelerates and decelerates uniformly. In this case, it is required to determine the number of revolutions done by the tub by means of the following equations of motion:

Acceleration

$\ddot n_{1} = \frac{\dot n_{1}-\dot n_{1,o}}{t_{1}}$ (Eq. 1)

Where:

$\ddot n_{1}$ - Angular acceleration experimented by the tub, measured in revolutions per square second.

$\dot n_{1,o}$ , $\dot n_{1}$ - Initial and final angular velocities of the tub, measured in revolutions per second.

$t_{1}$ - Acceleration time, measured in seconds.

$\Delta n_{1} = \dot n_{1,o}\cdot t_{1}+\frac{1}{2}\cdot \ddot n_{1}\cdot t_{1}^{2}$ (Eq. 2)

Where $\Delta n_{1}$ is the change in angular position of the tub during acceleration, measured in revolutions.

Deceleration

$\ddot n_{2} = \frac{\dot n_{2}-\dot n_{1}}{t_{2}}$ (Eq. 3)

Where:

$\ddot n_{2}$ - Angular acceleration experimented by the tub, measured in revolutions per square second.

$\dot n_{1}$ , $\dot n_{2}$ - Initial and final angular velocities of the tub, measured in revolutions per second.

$t_{2}$ - Deceleration time, measured in seconds.

$\Delta n_{2} = \dot n_{1}\cdot t_{2}+\frac{1}{2}\cdot \ddot n_{2}\cdot t_{2}^{2}$ (Eq. 4)

If we know that $\dot n_{1,o} =0\,\frac{rev}{s}$ , $\dot n_{1} = 5\,\frac{rev}{s}$ , $t_{1} = 7\,s$ , $\dot n_{2} = 0\,\frac{rev}{s}$ and $t_{2} = 8\,s$ , then the amount of revolutions done by the tub during each phase is, respectively: