Answer:
586 kpa(kilopascal/1000 pascals)
Explanation:
given 1.24 atm(standard atmosphere), and 66.7 psi(pound force per square inch).
To find the total pressure we should use dalton's law of partial pressures which is the sum of the pressures of each individual gas.
then we convert them to pascals and divide by 1000 to get the measurement in kilopascal.
knowing that 1 atmosphere is proportional to around 14.696 psi. We can multiply our given measure of atm by that and sum it by psi like so. 1.24×14.6959 = 18.22298.
Then,
18.22298+ 66.7 = 84.92298
psi.
Since 1 psi is proportional to around 6894.76 pascals. 1 psi will be 68.9476 kilopascal. 84.92298 * 6.89476 = 585.523336 ≈ 586
The synthetic compound Zn(C2H3O2)2 is zinc acetic acid derivation. The molecular composition demonstrates that the mixes incorporate zinc, spoke to by Zn; carbon, spoke to by C; hydrogen, spoke to by H; and oxygen, spoke to by O. Below is the <span>an equation that shows how the anion acts as a base:
</span>
C2H3O2−(aq)+H2O(l)⇌<span>HC2H3O2(aq)+OH−(aq)</span>
I think the subatomic particles that are paired with each of their corresponding name would be :
1. X , proton and z, electron
hope this helps
The mole fraction of HNO3 is 0.225
<u>Explanation:</u>
<u>1.</u>Given data
Density = 1.429 /ml
Mass% = 63.01 g HNO3 / 100g of solution
The mass of 63.01 g is in 100 / 1.142 /ml of solution
Or 63.01 g in 55.7 mL
Molarity = 15.39 moles / L
Mass of water in 100g = 100 - 63.01=36.99 g
So 63.01 grams in 36.99 grams of water
So mass of HNO3 in 1000grams of water = 63.01* x 1000 / 36.99 = 1703
Moles of HNO3 in 1000g = 1703 / 63.01 = 27.03 moles
Molality = 27.03 molal (mole / Kg)
Mole fraction = Mole of HN03 / Moles of water + mole of HNO3
Mole of water = 62/ 18 = 3.44
Moles of HNO3 = 63.01 / 63.01 = 1.000
Mole fraction = 1.000 / 3.44 + 1.000 = 0.225
The mole fraction of HNO3 is 0.225
Answer:
Explanation:
mass of aluminum 2.8 kg = 2.8 x 1000 = 2800 g
ρ = density of aluminum given = 2.7 g / cm³
density = mass / volume
volume = mass / density
= 2800 / 2.7
= 1037 cm³
So volume of cube required = 1037 cm³.
