Answer:
Public water supply and sanitation in the United Kingdom is characterised by universal access and generally good service quality[citation needed]. A salient feature of the sector in the United Kingdom compared to other developed countries is the diversity of institutional arrangements between the constituting parts of the UK (England and Wales; Scotland; and Northern Ireland), which are each described in separate articles, while this article is devoted to some common issues across the United Kingdom.
First, 1 foot = 30.48cm (12 inches x 2.54 cm/inch=30.48 cm). So, 8,5 ft = 8.5 x 30.48cc=259.08 cm, 7.5 ft = 7.5 x 30.48=228.6cm and 9.5/12=0.791ft x 30.48 =24.11cm. So, in cc, 259.08 x 228.6 x 24.11 = 1,427,931.3 cc. Since 1 cc of water = 1 gram then we have 1,427,931`grams or 1427. 931 kg x 2.2 lbs/kg = 3141 pounds of water or 1.57 tonnes of water so with this size of waterbed if upstairs the house structure must be able to withstand this stress.
Answer:
Explanation:
The formula of the reaction:
KClO₂ → KCl + O₂
To assign oxidation numbers, we have to obey some rules:
- Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
- The charge on simple ions signifies their oxidation number.
- The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.
The oxidation number of K in KClO₂:
K + (-1) + 2(-2) = 0
K-5 = 0
K = +5
The oxidation number of K in KCl:
K + (-1) = 0
K = +1
The oxidation number Cl in KClO₂ is -1
For Cl in KCl, the oxidation number is -1
For O in KClO₂, the oxidation number is (2 x -2) = -4
For O in O₂, the oxidation number is 0
K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.
O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.
<u>Answer:</u> The mass of sodium chloride solution present is 0.256 grams.
<u>Explanation:</u>
We are given:
39.0 % of sodium in sodium chloride solution
This means that 39.0 grams of sodium is present in 100 grams of sodium chloride solution
Mass of sodium given = 100 mg = 0.1 g (Conversion factor: 1 g = 1000 mg)
Applying unitary method:
If 39 grams of sodium metal is present in 100 grams of sodium chloride solution
So, if 0.1 grams of sodium metal will be present in = 
of sodium chloride solution.
Hence, the mass of sodium chloride solution present is 0.256 grams.
Answer:
Uh first of all this is algebra but I'll answer this
First distribute the three and 5 (Multiply them by both terms inside parenthesis.
3x-6=5x+20
Then add like terms
8x=14
Divide 8 by 8 and 8 by 14
x = 14/8
Explanation:
