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Semenov [28]
3 years ago
8

3 unhelpful frictional forces

Physics
2 answers:
Alex3 years ago
7 0
Friction the force that oppose motion so it unhelpful where all the motion of an object  is desired.that is what i know.
lutik1710 [3]3 years ago
5 0
All I know is that friction is unhelpful as it can make things stiff and difficult to use, sorry if this siding help.
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In fatal crashes, more than __________% of passenger car occupants who were totally ejected from the vehicle were killed.
Ierofanga [76]

Answer:

it would be 83% in a fatal crash.

8 0
3 years ago
Ree is 27 inches tall on her first birthday. She grows around 6 inches per year after that. What is the rate of change for the s
RSB [31]

Answer:

6

Explanation:

The rate of change in this scenario corresponds to the number of inches that Ree grows every year. Basically, Ree's height can be written as a linear equation as follows:

y=mx+q

where

x is the number of years after the first birthday

y is the height in inches

q = 27 is the height of Ree on her first birthday

m = 6 is the inches gained by Ree at each birthday

So the equation can also be rewritten as

y = 6x + 27

4 0
4 years ago
Read 2 more answers
A 1-kg plastic block is neutrally buoyant when submerged in water with a density of 1 g/cm3. If the same block is placed, such t
goldenfox [79]

Answer:

-2 m/s

Explanation:

The computation of the acceleration of the block is as follows:

The volume of the block is

V = 1kg ÷ 1,000 kg/m^3 = 1 ÷ 1,000 m^3

Now at the time of submerging in the oil

Net force is

m_g - F_B = m \times (-a)\\\\m_g - v\times S_{oil} \times g = -ma\\\\a = (\frac{v}{m} \times S_{oil}  - 1) g\\\\= (\frac{1}{1000} \times 0.8 \times 1000 -1 ) \times 10\\\\

= -2 m/s

8 0
3 years ago
A 2.7-kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0 m high cliff. At the instant the ball i
scoray [572]

Answer:

The distance traveled by the woman is 34.1m

Explanation:

Given

The initial height of the cliff

yo = 45m final, positition y = 0m bottom of the cliff

y = yo + ut -1/2gt²

u = 20.0m/s initial speed

g = 9.80m/s²

0 = 45.0 + 20×t –1/2×9.8×t²

0 = 45 +20t –4.9t²

Solving quadratically or by using a calculator,

t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s

So this is the total time it takes for the ball to reach the ground from the height it was thrown.

The distance traveled by the woman is

s = vt

Given the speed of the woman v = 6.00m/s

Therefore

s = 6.00×5.69 = 34.14m

Approximately 34.1m to 3 significant figures.

3 0
3 years ago
A go cart starts from REST and accelerates uniformly over a time of 7 seconds for a distance of 100m. Determine the acceleration
Hunter-Best [27]

Answer:

please find attached pdf

Explanation:

Download pdf
6 0
3 years ago
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