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2 years ago

Which of the following is a transformer used for?

2 answers:

5 0

A transformer is used to increase or decrease a voltage. BUT ... it has to be an AC voltage, or the transformer doesn't work.

denis23 [38]2 years ago

5 0

Answer: Increase or decrease a voltage

Explanation: Transformers are designed for increasing or decreasing the voltage in an electrical circuit, using the principle of electromagnetic induction.

These only work with alternating currents, because this alternating current drifts in the generation of permanent magnetic flux. The arrangement to make this possible consists of a pair of coils with a number of different spirals isolated from each other, and a ferromagnetic material is added to the core to optimize the magnetic flux. Thanks to the different number of spirals in the coils the increase or decrease of the voltage is achieved.

The voltage transformation follows the following mathematical formula:

$\frac{V_{s} }{V_{p} }=\frac{N_{s} }{N_{p} }$

Where

[tex]\V_{s} = Secondary voltage

[tex]\V_{p} = Primary voltage

[tex]\[N_{s} = Secondary number of spirals

[tex]\N_{p} = Primary number of spirals

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1 year ago

What could be the possible answer to the question ? thankyou ~

Ganezh [65]

The value of the force, F₀, at equilibrium is equal to the horizontal

component of the tension in string 2.

Response:

The value of F₀ so that string 1 remains vertical is approximately 0.377·M·g

<h3>How can the equilibrium of forces be used to find the value of F₀?</h3>

Given:

The weight of the rod = The sum of the vertical forces in the strings

Therefore;

M·g = T₂·cos(37°) + T₁

The weight of the rod is at the middle.

Taking moment about point (2) gives;

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Therefore;

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Which gives;

$M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}$

$T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})} = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}$

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Which gives;

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F₀ ≈ 0.377·M·g

Learn more about equilibrium of forces here:

brainly.com/question/6995192

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