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o-na [289]
3 years ago
7

Which of the following is a transformer used for?

Physics
2 answers:
mamaluj [8]3 years ago
5 0

A transformer is used to increase or decrease a voltage.  BUT ... it has to be an AC voltage, or the transformer doesn't work.

denis23 [38]3 years ago
5 0

Answer: Increase or decrease a voltage

Explanation: Transformers are designed <u>for increasing or decreasin</u>g the voltage in an electrical circuit, using the principle of e<em>lectromagnetic induction</em>.

These only work with alternating currents, because this alternating current drifts in the generation of permanent magnetic flux. The arrangement to make this possible consists of a pair of coils with a number of different spirals isolated from each other, and a ferromagnetic material is added to the core to optimize the magnetic flux.  Thanks to the different number of spirals in the coils the increase or decrease of the voltage is achieved.

The voltage transformation follows the following mathematical formula:

\frac{V_{s} }{V_{p} }=\frac{N_{s} }{N_{p} }

Where

[tex]\V_{s} =  Secondary voltage

[tex]\V_{p} = Primary voltage

[tex]\[N_{s} = Secondary number of spirals

[tex]\N_{p} = Primary number of spirals

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Using a calculator, the answer will be 1/2 as a result of all the / and use of opposite πs that form 18 making a whole circle.
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A 1.50 V potential difference is maintained across a 1.50 m wire that has a cross-sectional area of 0.600 mm2. How much power is
Goshia [24]

Given that the potential difference is V = 1.5 V.

The length of the wire is l = 1.5 m.

The cross-sectional area is

\begin{gathered} A\text{ = 0.6 }mm^2 \\ =0.6\times10^{-6}m^2 \end{gathered}

The resistivity of the wire is

\rho\text{ = 5.25}\times10^{-8}\Omega\text{ m }

We have to find the power dissipated in the wire.

First, we need to calculate resistance.

The resistance can be calculated as

\begin{gathered} R\text{ = }\rho\frac{l}{A} \\ =5.25\times10^{-8}\times\frac{1.5}{0.6\times10^{-6}} \\ =0.13125\Omega \end{gathered}

The formula to calculate power is

P\text{ =}\frac{V^2}{R}

Substituting the values, the power will be

\begin{gathered} P\text{ = }\frac{(1.5)^2}{0.13125} \\ =17.1\text{ W} \end{gathered}

Thus, the power dissipated in the wire is 17.1 W

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2 years ago
a person jogs eight complete laps around a 400-m track in a total time of 15.1 min .calculate the average speed, in m/s .
valentinak56 [21]

The average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

<h3>How to calculate average speed?</h3>

Average speed of a moving body can be calculated by dividing the distance moved by the time taken.

Average speed = Distance ÷ time

According to this question, a person jogs eight complete laps around a 400m track in a total time of 15.1 min. The average speed is calculated as follows:

15.1 minutes in seconds is as follows = 906 seconds

Average speed = 400m ÷ 906s

Average speed = 0.44m/s

Therefore, the average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

Learn more about average speed at: brainly.com/question/12322912

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