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3 years ago

Which of the following is a transformer used for?

2 answers:

5 0

A transformer is used to increase or decrease a voltage. BUT ... it has to be an AC voltage, or the transformer doesn't work.

denis23 [38]3 years ago

5 0

Answer: Increase or decrease a voltage

Explanation: Transformers are designed <u>for increasing or decreasin</u>g the voltage in an electrical circuit, using the principle of e<em>lectromagnetic induction</em>.

These only work with alternating currents, because this alternating current drifts in the generation of permanent magnetic flux. The arrangement to make this possible consists of a pair of coils with a number of different spirals isolated from each other, and a ferromagnetic material is added to the core to optimize the magnetic flux. Thanks to the different number of spirals in the coils the increase or decrease of the voltage is achieved.

The voltage transformation follows the following mathematical formula:

$\frac{V_{s} }{V_{p} }=\frac{N_{s} }{N_{p} }$

Where

[tex]\V_{s} = Secondary voltage

[tex]\V_{p} = Primary voltage

[tex]\[N_{s} = Secondary number of spirals

[tex]\N_{p} = Primary number of spirals

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What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use

marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force $F_{1}=18\ N$

Force $F_{2}=26\ N$

Force $F_{3}=14\ N$

We need to calculate the torque due to force F₁

Using formula of torque

$\tau_{1}=-F_{1}d_{1}$

$\tau_{1}=-F_{1}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{1}=-18\times\dfrac{0.2}{2}$

$\tau_{1}=-1.8\ N-m$

We need to calculate the torque due to force F₂

Using formula of torque

$\tau_{2}=F_{2}d_{2}$

$\tau_{2}=F_{2}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{2}=26\times\dfrac{0.2}{2}$

$\tau_{2}=2.6\ N-m$

We need to calculate the torque due to force F₃

Using formula of torque

$\tau_{3}=F_{3}d_{3}$

$\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{3}=0.1(14\sin45+14\cos45)$

$\tau_{3}=1.92\ N-m$

We need to calculate the net torque on the square plate

$\tau=\tau_{1}+\tau_{2}+\tau_{3}$

$\tau=-1.8+2.6+1.92$

$\tau=2.72\ N-m$

Hence, The net torque on the square plate is 2.72 N-m.

3 0

3 years ago

Use the drop-down menus to identify the parts of the

DochEvi [55]

Answer:

Label A: Battery, Label B: Light or Bulb, Label C: Switch

Explanation:

I got it right.

5 0

3 years ago

What distance is covered by an airplane traveling at a velocity of 660 miles per hour in 3.5 hours?

N76 [4]

As per the question, the velocity of the airplane [v] = 660 miles per hour.

The total time taken by airplane [t] = 3.5 hours.

We are asked to determine the total distance travelled by the airplane during that period.

The distance covered [ S] by a body is the product of velocity with the time.

Mathematically distance covered = velocity × total time

S = v × t

= 660 miles/hour ×3.5 hours

= 2310 miles.

Hence, the total distance travelled by the airplane in 3.5 hour is 2310 miles.

4 0

3 years ago

Assume that the blocks are accelerating, and the x components of their accelerations at a certain moment are a1x and a2x. find t

Serga [27]

we know that center of mass is given as

r = (m₁ $r_{1x}$ + m₂ $r_{2x}$ )/(m₁ + m₂)

taking derivative both side relative to "t"

dr/dt = (m₁ d $r_{1x}$ /dt + m₂ d $r_{2x}$ /dt)/(m₁ + m₂)

v = (m₁ $v_{1x}$ + m₂ $v_{2x}$ )/(m₁ + m₂)

taking derivative again relative to "t" both side

dv/dt = (m₁ d $v_{1x}$ /dt + m₂ d $v_{2x}$ /dt)/(m₁ + m₂)

a= (m₁ $a_{1x}$ + m₂ $a_{2x}$ )/(m₁ + m₂)

3 0

3 years ago

Read 2 more answers

A farmhand attaches a 25-kg bale of hay to one end of a rope passing over a

Georgia [21]

Explanation:

Newton's second law:

∑F = ma

277 N − 245 N = (25 kg) a

a = 1.28 m/s²

8 0

3 years ago