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o-na [289]
3 years ago
7

Which of the following is a transformer used for?

Physics
2 answers:
mamaluj [8]3 years ago
5 0

A transformer is used to increase or decrease a voltage.  BUT ... it has to be an AC voltage, or the transformer doesn't work.

denis23 [38]3 years ago
5 0

Answer: Increase or decrease a voltage

Explanation: Transformers are designed <u>for increasing or decreasin</u>g the voltage in an electrical circuit, using the principle of e<em>lectromagnetic induction</em>.

These only work with alternating currents, because this alternating current drifts in the generation of permanent magnetic flux. The arrangement to make this possible consists of a pair of coils with a number of different spirals isolated from each other, and a ferromagnetic material is added to the core to optimize the magnetic flux.  Thanks to the different number of spirals in the coils the increase or decrease of the voltage is achieved.

The voltage transformation follows the following mathematical formula:

\frac{V_{s} }{V_{p} }=\frac{N_{s} }{N_{p} }

Where

[tex]\V_{s} =  Secondary voltage

[tex]\V_{p} = Primary voltage

[tex]\[N_{s} = Secondary number of spirals

[tex]\N_{p} = Primary number of spirals

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A wave has a frequency of 15,500 Hz and a wavelength of 0.20 m. What is the
Hoochie [10]

Answer:

3100 m/s

Explanation:

The relationship between frequency and wavelength of a wave is given by the wave equation:

v=f\lambda

where

v is the speed of the wave

f is its frequency

\lambda is the wavelength

For the wave in this problem,

f = 15,500 Hz

\lambda=0.20 m

Therefore, the wave speed is

v=(15500)(0.20)=3100 m/s

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3 years ago
__________ are scientists that study the composition of earth including rock layers at the surface.
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Answer:

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Explanation:

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When looking at liquids in a container, that have layered on one another;
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3 years ago
A point charge Q moves on the x-axis in the positive direction with a speed of A point P is on the y-axis at The magnetic field
oee [108]

Answer: q = -52.5 μC

Explanation:

The complete question is given thus;

A point charge Q moves on the x-axis in the positive direction with a speed of 280 m/s. A point P is on the y-axis at y=+70mm. The magnetic field produced at the point P, as the charge moves through the origin, is equal to -0.30uTk. What is the charge Q? (uo=4pi x 10^-7 T m/A).

SOLVING:

from the given parameters we can solve this problem.

Given that the

Speed = 280 m/s

y = 70mm

B =  -30 * 10⁻⁶T

Using the equation for magnetic field we have;

Β = μqv*r / 4πr²

making q (charge) the subject of formula we have that;

q  = B * 4 *πr² / μqv*r

substituting the values gives us

q = (-0.3*10⁻⁶Tk * 4π * 0.07²) / (4π*10⁻⁷ * 280 ) = - [14.7 * 10⁻¹⁰k / 2.8 * 10⁻⁵ k ]

q = -52.5 μC

cheers i hope this helped !!!

3 0
3 years ago
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