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gtnhenbr [62]
2 years ago
8

A coil of standard annealed copper having a resistance of 50 ohms at 15° is embedded in the core of a large transformer after th

e transformer has been in operation for several hours the resistance of the material is measured as 58 ohms determine its temperature the temperature coefficient of resistance of the conductor material is 0.04 250 degree celsius at 0 degrees Celsius.
determine its temperature?​
Physics
1 answer:
iren [92.7K]2 years ago
8 0

The temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.

<h3>Relationship between resistance and temperature</h3>

The relationship between resistance and temperature is given as;

R = R₀( 1 + αΔθ)

From the first resistance, we will have the following equation,

R₁ = R₀( 1 + αΔθ)

50 = R₀(1 + 15α) ------ (1)

From the second resistance, we will have the following equation,

58 = R₀(1 + αT) ------ (2)

Divide (1) by (2)

\frac{50}{58} = \frac{R_0(1 + 15\alpha)}{R_0(1 + T\alpha)} \\\\\frac{50}{58} = \frac{(1 + 15\alpha)}{(1 + T\alpha)} \\\\50(1 + T\alpha) = 58(1 + 15\alpha)\\\\50 + 50T\alpha = 58 + 870\alpha \\\\50(0.0425)T = (58- 50) + 870(0.0425)\\\\2.125T = 44.975\\\\T = 21.2\ ^0C

Thus, the temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.

Learn more about resistance and temperature here: brainly.com/question/2735534

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kenny6666 [7]

Answer:

The charge flos through the coil is 0.023C

Explanation:

To solve this problem, it is necessary to apply the concepts related to Faraday's Law in which it is possible to calculate the emf Voltage induced due to a charge in a magnetic field

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Our data are given by:

N=100

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Where

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V = \frac{dq}{dt} R

Equating both equations we have

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We can re-arrange the equations to solve q, then

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Therefore the charge flos through the coil is 0.023C

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Answer:

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Explanation:

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