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Yakvenalex [24]
3 years ago
6

A go cart starts from REST and accelerates uniformly over a time of 7 seconds for a distance of 100m. Determine the acceleration

.
Physics
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

please find attached pdf

Explanation:

Download pdf
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What is a parellogram?​
Sergio [31]

Answer:

a four-sided plane rectilinear figure with opposite sides parallel.

3 0
3 years ago
Un bombero alejado d = 31.0 m de un edificio en llamas dirige un chorro de agua desde una manguera contra incendios a nivel del
Mila [183]

Answer:

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

Explanation:

El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:

Distancia horizontal (en metros)

x = x_{o} + v_{o}\cdot t \cdot \cos \theta

Donde:

x_{o} - Posición horizontal inicial, medida en metros.

t - Tiempo, medido en segundos.

v_{o} - Velocidad inicial, medida en metros por segundo.

\theta - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.

Distancia vertical (en metros)

y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}

Donde:

y_{o} - Posición vertical inicial, medida en metros.

g - Constante gravitacional, medida en metros por segundo al cuadrado.

Partiendo de la primera ecuación, se despeja el tiempo:

t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}

Si x = 31\,m, x_{o} = 0\,m, v_{o} = 40\,\frac{m}{s} and \theta = 33^{\circ}, entonces:

t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}

t = 0.924\,s

La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si y_{o} = 0\,m, v_{o} = 40\,\frac{m}{s}, t = 0.924\,s y g = -9.807\,\frac{m}{s^{2}}, entonces:

y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}

y = 15.943\,m

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

3 0
3 years ago
A cross-country skier can complete a 7. 5 km race in 45 min. What is the skier’s average speed? km/h.
never [62]

The average speed is a scalar quantity. The average speed of the skier is 10 km/hrs.

<h3>What is the average speed?</h3>

It is calculated by dividing the total distance by the total time elapsed.

The

\overline{v}={\frac{\Delta x}{\Delta t}}

Where,

\overline{v} = average velocity

{\Delta x} = displacement = 7.5 km

{\Delta t} = change in time = 45  min = 0.75 hours

Put the values in the formula,

\overline{v}={\frac{7.5 }{0.75 }}\\\\\overline{v}= 10 \rm \ km/hrs

Therefore, the average speed of the skier is 10 km/hrs.

Learn more about average speed:

https://brainly.in/question/32459982

8 0
3 years ago
Incline plane examples from daily life
Sergeeva-Olga [200]
Examples of inclined planes are ramps, sloping roads and hills, plows, chisels, hatchets, carpenter's planes, and wedges.
5 0
3 years ago
An engine has an imput of 100 j and gives out 27 j of useful kenetic energy what is the efficiency of the engine
Lunna [17]

Answer:

Based on what we have learned so far, in what ways have the experiences of Asian-Canadians stayed the same over time? Why do you think these similarities exist? Please give specific examples to support your ideas.

Explanation:

4 0
3 years ago
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