Answer:
Step-by-step explanation:
3*3+2/3-2*6+5/6
=9+2/3-12+5/6
=11/3-17/6
take lcm of the denominator
=11*2-17*1/6
=22-17/6
=5/6
1 - Derivative of arcsin x.
<span>
The derivative of f(x) = arcsin x is given by
</span><span> f '(x) = 1 / sqrt(1 - x 2) </span><span>
</span>2 - Derivative of arccos x.
<span>
The derivative of f(x) = arccos x is given by
</span><span> f '(x) = - 1 / sqrt(1 - x 2) </span><span>
</span>3 - Derivative of arctan x.
<span>
The derivative of f(x) = arctan x is given by
</span><span> f '(x) = 1 / (1 + x 2) </span><span>
</span>4 - Derivative of arccot x.
<span>
The derivative of f(x) = arccot x is given by
</span><span> f '(x) = - 1 / (1 + x 2) </span><span>
</span>5 - Derivative of arcsec x.
<span>
The derivative of f(x) = arcsec x tan x is given by
</span><span> f '(x) = 1 / (x sqrt(x 2 - 1))</span><span>
</span>6 - Derivative of arccsc x.
<span>
The derivative of f(x) = arccsc x is given by
</span><span> f '(x) = - 1 / (x sqrt(x 2 - 1)) </span><span>
</span>
Please help with at least one question I’m really stressed
Answer:
The new car costs more
Old car = $5062.125
New car = $7161.357
Step-by-step explanation:
Manny drives an average of 110 miles per week with his old car. The old car gets 16 miles per gallon. The cost per gallon is $2.65 repair and Maintainance costs an average of $740 per year.
For the old car, to find the amount spent on the car we have
110/16 * 2.65 = $18.21875 / week
There are 52 weeks in a year. We have
10.21875*52 = $ 947.375
947.375 + 740
= $1687.375
= 1687.357 * 3
= $5062.125
The new car cost $6500 over a three year loan process.
The car gets 28 miles per gallon. It requires a maintenance f $10 per month. For the new car to find the amount, we have
110*28 * 2.65 *52 = $541.357
541.357 + 10(12) + 6500
= $7161.357
Answer:
Option A would be your answer
Step-by-step explanation:
Had this question on Achieve3000
