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creativ13 [48]
2 years ago
15

The value of x varies directly with y, and when x= 1/3,y = 12. Write an equation to represent the direct variation.

Mathematics
1 answer:
shtirl [24]2 years ago
5 0

Answer:

Equation: y = 36x

Step-by-step explanation:

The equation that represents a direct variation between variable x and variable y is given as y = kx. Where, k is the constant of proportionality.

Find the value of k given that x = ⅓ and y = 12.

Plug the values into the equation.

y = kx

12 = k\frac{1}{3}

Multiply both sides by 3

12*3 = k*1

36 = k

Substitute the value of k into y = kx

y = 36x

Equation: y = 36x

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Neporo4naja [7]

Answer:

Here to help!

Step-by-step explanation:

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7 0
3 years ago
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An arrow is launched upward with a velocity of 192 feet per second from the top of a 95-foot stage. What is the maximum height a
Shalnov [3]

9514 1404 393

Answer:

  671 feet

Step-by-step explanation:

There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².

  v² = 2ad

  d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft

This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...

  max height = 95 ft + 576 ft = 671 ft

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Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...

  h(t) = -16t^2 +192t +95

The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:

  t = -(192)/(2(-16)) = 6

Then the maximum height is ...

  h(6) = -16·6^2 +192·6 +95 = 671

The maximum height is 671 feet.

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<em>Additional comment</em>

For the standard-form quadratic ...

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The axis of symmetry is ...

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6 0
3 years ago
What is the length of the TV if it is 45.25 inches wide and 24.5 inches tall ?
Vsevolod [243]

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We already have wide for width

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3 years ago
You are choosing a new cell phone. The screen on your current phone is 10.8 cm high and 6.1 cm wide. The screen on the new phone
Leto [7]

Answer:

19.68 cm^2

Step-by-step explanation:

<em>Area of Current Phone </em>

First, find the area of the current phone. We can assume the screen is rectangular. The area of a rectangle can be found using:

a=l*w

We know the length is 10.8, and the width is 6.1, so we can substitute them in

a=10.8*6.1

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Current Phone: 65.88 cm^2

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<em>Difference </em>

We want to find how much larger the new phone screen is. To do this, find the difference between the new phone area, and the current phone area.

new phone - current phone

85.56-65.88

19.68

<em><u>The new phone screen is 19.68 cm^2 larger than the current phone screen</u></em>

7 0
3 years ago
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sineoko [7]

Answer: station X

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