Slope i cant seem to figure out run/rise can anyone also help me with that too thank you

algebraically determine the values of h and k to correctly complete the identity stated below : 2 x cubed - 10x squared + 11x -

11Alexandr11 [23.1K]

Answer:

The values for expression is h = - 2 and k = 5

Step-by-step explanation:

Given algebraic expression can be written as :

2 x³ - 10 x² + 11 x - 7 = ( x - 4 ) × ( 2 x² + h x + 3 ) + k

Now opening the bracket

Or, 2 x³ - 10 x² + 11 x - 7 = x × ( 2 x² + h x + 3 ) - 4 × ( 2 x² + h x + 3 ) + k

Or, 2 x³ - 10 x² + 11 x - 7 = 2 x³ + h x² + 3 x - 2 x² - 4 h x - 12 +k

Or , 2 x³ - 10 x² + 11 x - 7 = 2 x³ + ( h - 2 ) x² + ( 3 - 4 h ) x - 12 + k

Now, equating the equation both sides

I.e - 10 = ( h - 2 )

Or , h - 2 = - 10

I.e , h = - 10 + 2

∴ h = - 2

Again , 11 = ( 3 - 4 h )

or, 11 = 3 - 4 h

or, 11 - 3 = - 4 h

or, 8 = - 4 h

∴ h = $\frac{-8}{4}$

I.e h = - 2

Again

- 7 = - 12 + k

Or, k = - 7 + 12

∴ k = 5

Hence The values for expression is h = - 2 and k = 5 . Answer

5 0

2 years ago

How can I solve these problems

Anuta_ua [19.1K]

Here’s the first few and you can do the rest with the same principles. If you need more help with the last ones then let me know

4 0

3 years ago

A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32

zavuch27 [327]

$Hypotenuse =39cm$ of right angle triangle! .

<u>Step-by-step explanation:</u>

Here we have , A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32 centimeters, and the length of the other leg is 25 centimeters. The student incorrectly says that the length of the hypotenuse is 7.5 centimeters. We need to find:

A)

We have , One length as 32 cm and other as 25 cm , as

$Perpendicular = 32cm\\Base=25cm$

By Pythagoras Theorem ,

⇒ $Hypotenuse^2 = Perpendicular^2+Base^2$

⇒ $Hypotenuse^2 =32^2+22^2$

⇒ $\sqrt{Hypotenuse^2} =\sqrt{1024+484}$

⇒ $Hypotenuse =39cm$

So , $Hypotenuse =39cm$ of right angle triangle! .

4 0

3 years ago

Read 2 more answers

Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), x

kumpel [21]

Answer:

12m

Step-by-step explanation

If the height of the ball after x seconds be modelled by the equation

h(x)=−(x−2)² +16

The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0

To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;

h(0) = -(-0-2)²+16.

h(0) = -(-2)²+16

h(0) = -4+16

h(0) = 12

The height of the ball at the time the ball is thrown is 12m

4 0

3 years ago

Read 2 more answers

8x-5y=21 simultaneous linear equation<br>2x+9y=-5

olya-2409 [2.1K]

Answer:

$x=2$ and $y=-1$

Step-by-step explanation:

If two equations are given, we can solve one of the equation in terms of single variable and put it in the other equation which will further give the value of x and y.

For the given equations:

$8x-5y=21$ Equation:1