Answer:
The flagpole's shadow is 16.875 feet longer than the man's shadow
Step-by-step explanation:
The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;
Height of the shadow=actual height of the flagpole×factor
where;
length of the flagpole's shadow=22.5 feet
actual height of the flagpole=32 feet
factor=f
replacing;
22.5=32×f
32 f=22.5
f=22.5/32
f=0.703125
Using this factor in the expression below;
Length of man's shadow=actual height of man×factor
where;
length of man's shadow=m
actual height of man=8 feet
factor=0.703125
replacing;
length of man's shadow=8×0.703125=5.625 feet
Determine how much longer the flagpole's shadow is as follows;
flagpoles shadow-man's shadow=22.5-5.625=16.875 feet
The flagpole's shadow is 16.875 feet longer than the man's shadow
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The only math term I can think of is geometry and it means when a solid is cut through parallel to the base.
EDIT: After further research since it was all I could think of. This is the only math term for what you are looking for.
Answer:
vw= 22
Step-by-step explanation:
To find the dot product of vw, multiply the corresponding numbers and add them.
v= <3, -8, -3> w= <-4, -2, -6>
vw= (3*-4)+(-8*-2)+(-3*-6)
vw= -12+16+18
vw= 4+18
vw= 22
