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inn [45]
3 years ago
9

Using Suitable Identity ,Find the value of (i) (729)2-(271)2 (ii)98x107

Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:

(i) 458000 (ii) 10486

Step-by-step explanation:

(i) (729)²-(271)²

The identity is : a^2-b^2=(a-b)(a+b)

(729)²-(271)² = (729-271) × (729+271)

= 458 × 1000

= 458000

(ii) 98x107 = (100-2) (100+7)

Idenity : (x-a)(x-b) = x^2+(a+b)x+ab

(100-2) (100+7)=100^2+(-2+7)100+(-2)(7)\\\\=10000+500-14\\\\=10486

Hence, this is the required solution.

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34.23 times one year is ....
kenny6666 [7]

Answer:

410.76

Step-by-step explanation:

34.23 * 12= 410.76

1 year = 12 months

5 0
3 years ago
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there are 305 crayons in a box and 213 crayons on the floor. About how many fewer than 1000 crayons are there?estimate Then solv
OleMash [197]
305+213=518

1000-518= 482

The answer is there is 482 less crayons then a thousand
6 0
3 years ago
HELPPPPP
soldi70 [24.7K]

x=50  

Step-by-step explanation:

angle 1 and 3 are corresponding angles that menas they equal the same

so set it up like this 2x+10=110 solve for x

move over the 10, subtract 10 from 110 you get 100 and divide by 2

you get 50.

8 0
3 years ago
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The box and whisker plots below show two classes' semester grades. Write a paragraph comparing the two sets of
oksano4ka [1.4K]

The paragraph to show the comparision between two classes semester grades on the basis of the terms

  • extremes
  • quartiles
  • medians
  • ranges

is given below:

<h3>What is Box and Whisker plots?</h3>

A box and whisker plot is defined as a graphical method of displaying variation in a set of data.

From the first figure, write all the values where dark point is drawn

53, 62, 80, 86, 89  

  • The lower extreme is the smallest value, which is 53.

        The upper extreme is the highest value, which is 89.

  • The median will be the middle of data , which is 80

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

        The upper quartile is 86 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =89-53

       =36

From the second figure, write all the values where dark point is drawn

56, 62, 74, 89, 96

  • The lower extreme is the smallest value, which is 56.

        The upper extreme is the highest value, which is 96.

  • The median will be the middle of data , which is 74.

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

       The upper quartile is 89 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =96-62

       =34

From the above discussion,  

  • The First class have less upper extreme value than the second class.
  • The First class have less lower extreme value than the second class.
  • The First class have greater median than the second class.
  • The First class have less upper quartile than the second class.
  • The First and second class have equal lower quartile.
  • The First class have greater range than the second class.

The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.

learn more about box and whisper plot here:

brainly.com/question/11859288

#SPJ1

6 0
2 years ago
DJ Titus is making a playlist for a radio show; he is trying to decide what 10 songs to play and in what order they should be pl
Dominik [7]

Answer:

Different playlists possible = 18287141644800

Step-by-step explanation:

Given - DJ Titus is making a playlist for a radio show; he is trying to

            decide what 10 songs to play and in what order they should be

            played.

            Step 1 of 2 : If he has his choices narrowed down to 7 blues,

                                 7 disco, 5 pop, and 7 reggae songs.

To find - He wants to play no more than 4 reggae songs.

              How many different playlists are possible ?

Proof -

Given that he wants to play no more that 4 reggae songs.

So the possibility of choice of reggae song is 0, 1, 2, 3, 4

Now,

Case I -

If 0 reggae song is selected

⇒All 10 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₁₀ ₓ ⁷C₀ = 92,378

Case II -

If 1 reggae song is selected

⇒All 9 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₉ ₓ ⁷C₁ = 646,646

Case III -

If 2 reggae song is selected

⇒All 8 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₈ ₓ ⁷C₂ = 1,587,222

Case IV -

If 3 reggae song is selected

⇒All 7 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₇ ₓ ⁷C₃ = 1,763,580

Case V -

If 4 reggae song is selected

⇒All 6 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₆ ₓ ⁷C₄ = 949,620

So,

Total possible ways = 92,378+ 646,646+ 1,587,222+ 1,763,580+ 949,620

                               = 5,039,446

⇒Total possible ways = 5,039,446

Now,

Also the 10 songs selected can arranged themselves in 10! ways. ( because order of song played does not matter )

∴ we get

Different playlists possible = 10! × 5,039,446

                                          = 18287141644800

⇒Different playlists possible = 18287141644800

6 0
3 years ago
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