Answer:
StartFraction B C Over Y Z EndFraction = StartFraction 6 Over 3 EndFraction
Step-by-step explanation:
It is stated that both triangles satisfy the Side Side Side (SSS) postulate, and the proportions between 2 sides are provided, therefore, the missing proportion is needed to prove that the triangles are similar, that proportion is: BC/YZ = 6/3
Answer:
14, 21, and 63
Step-by-step explanation:
we can set the three unknown numbers as x, y, and z
so
x + y + z =98
now we are given that the first (x) is seven less than the second (y)
x = y - 7
the third number (z) is three times the second (y)
z = 3y
since we have an equation for z and x in terms of y, we can plug it into the first equation and solve for y.
(y-7) + y + (3y) =98
y - 7 + y + 3y =98
y + y + 3y =105
5y = 105
y=21
now that we know y, we can plug its value into either the second or the third equation to find x or z (I chose to find z first)
z = 3y
z = 3(21)
z = 63
now we can plug in y to find x
x = y - 7
x = 21 - 7
x = 14
so the three numbers should be 14, 21, and 63
Perimeter is 36. This is because the radius and side lengths are the same in a regular hexagon.
Are is roughly 93.53.
Answer:
hello
Step-by-step explanation:
Answer:
65/97 or 0.67
Step-by-step explanation:
TanY = opposite/adjacent
TanY = XZ/YZ
TanY = 65/97
= 0.6701030928