Hello,
Let's put the 6 houses on side: 6P9=9*8*7*6*5*4/6! = 84
For each choice there are 3! choices pour the other side
84*3!=504
Answer:
2
Step-by-step explanation:
Order of operations is not as applicable in this situation because we're just dealing with addition and subtraction. This is a simple case of plugging in values for the given expression.
x = 3
z = 4
So it becomes...
3 + 3 - 4
6 - 4
2
So with the given expression of x + x - z and the given values of x = 3 and z = 4, the expression should sum to: 2
Answer:
D. If John owns a dog, then he owns a cat
Step-by-step explanation:
The implication p → q (if p, then q) has the same truth table as the logical expression ~p∨q. You have the expression ...
~(John owns a dog) ∨ (he owns a cat)
Matching parts of this expression to the components of the expression ~p∨q, we see we can choose ...
- p = John owns a dog
- q = he owns a cat
and put those into the structure of the implication: if p, then q.
If John owns a dog, then he owns a cat. . . . . matches choice D
Answer:
no
Step-by-step explanation:
3/6 is a ratio that is less than one and 6/3 is greater than one
think about them in their fraction form... ratios are forms of fractions
18 is the answer hood this will help you
