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3 years ago

9

(6•11)2 •2-4(-2+14)2-12 simplest terms

1 answer:

Ksju [112]3 years ago

8 0

Answer:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left[-10-\left(-6\right)\right]}{\left[4+5\right]\div \left[4^2\:−\:3^2\left(4−3\right)−8\right]+12}

Step-by-step explanation:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{4+5}{\left(4^2-3^2\left(4-3\right)-8\right)+12}}

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Which functions are symmetric with respect to the y-axis? Check all that apply.

xenn [34]

Answer:

f(x) = |x|, f(x) = [x] + 6

Step-by-step explanation:

Almost all of these are absolute values equations, which means the y doesn't change if x is positive or negative. The first one is the parent form, which is the simplest equation of the absolute equation, so it's symmetric with respect to the y-axis. The second equation is translated 3 units to the left, and the third is translated 31 to the left. The forth is translated 6 up, so it's still symmetric with respect to the y-axis. The fifth is translated 61 units left, and the last one is simply a line, which isn't symmetric.

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3 years ago

Graph the line passing through the given point and having the given slope (0,3), m=4

andriy [413]

<u>Hint </u><u>:</u><u>-</u>

To find out the equation of the line we can use the point slope form of the line which is $y - y_1 = m(x-x_1)$

<u>Solution</u><u> </u><u>:</u><u>-</u>

The given point to us is , $(0,3)$ and the slope of the line is 4 . On using the point slope form , we have ,

$\implies y - y_1= m(x-x_1) \\\\\implies y-3 = 4(x-0) \\\\\implies y -3 = 4x \\\\\implies \boxed{ 4x - y + 3 =0}$

<u>Hence</u><u> the</u><u> </u><u>equation</u><u> </u><u>is </u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>y </u><u>+</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>0</u><u> </u>

( for graph , see attachment ) .

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2 years ago

Hello, i was confused in this if anyone could help me with it

umka2103 [35]

Answer:

hmmmmmm Okay From what question?

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2 years ago

The volume of the cube below is 1/8cm^2 . What is the value of x?

Kipish [7]

We are given

edge of cube =x

we know that formula for volume of cube

$V=x^3$

we are given

$V=\frac{1}{8} cm^3$

we can plug value

$x^3=\frac{1}{8} cm^3$

now, we can solve for x

$\sqrt[3]{x^3} =\sqrt[3]{\frac{1}{8} cm^3 }$

$x=\frac{1}{2} cm$ ............Answer

6 0

3 years ago

Read 2 more answers

David made a scale drawing of an Olympic-sized pool the pool is 20.5 in long and the drawing that I can shoot pool is 164 ft lon

SIZIF [17.4K]

Answer:

$Scale = 1\ in : 8\ ft$

Step-by-step explanation:

Given

$Scale\ Measurement = 20.5in$

$Actual\ Measurement = 164ft$

Required

Determine the scale

The scale is calculated using the following ratio:

$Scale = Scale\ Measurement : Actual\ Measurement;$

Substitute values for Scale and Actual Measurements

$Scale = 20.5\ in : 164\ ft$

Divide ratio by 20.5

$Scale = 20.5/20.5\ in : 164/20.5\ ft$

$Scale = 1\ in : 8\ ft$

This implies that: <em>1 inch on scale represents 8 ft in actual measurement</em>

4 0

2 years ago

Read 2 more answers